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natulia [17]
3 years ago
15

Largest odd number by using all four (4) cards 5,3,2,6

Mathematics
1 answer:
dlinn [17]3 years ago
7 0

Answer:

6523

Step-by-step explanation:

I'm assuming that the question is asking us to rearrange the numbers 5,3,2,6 to obtain the largest possible value that is odd.

In order for a number to have the largest value, the first digit of the number must he the largest possible value. In this case, we see that the largest value is 6, hence the number must begin with 6 i.e 6XXX

We can do the same for the next digit in the hundreds position by picking the largest possible remaining number. In this case, it is the number 5. So the number will look something like this: 65XX

We see that the only  remaining numbers are 3 and 2.

Recall that for a number to be odd, the digit on the ones place must also be odd. Of the remaining numbers, only 3 is odd, hence the last number must be 3. i.e 65X3

Hence the last remaining number is 2

6523

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Answer:

a. This is a probability distribution as ∑pi=1

b. 2.72

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∑pi=0.32+0.12+0.23+0.18+0.15=1

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mean number of items=1*0.32+2*0.12+3*0.23+4*0.18+5*0.15=2.72

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∑x²*p(x)=1*0.32+4*0.12+9*0.23+16*0.18+25*0.15=9.5

(∑x*p(x))²=(2.72)²=7.4

standard deviation of number of items=sqrt[(∑x²*p(x))-(∑x*p(x))²]=sqrt(9.5-7.4)=sqrt(2.1)=1.45

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2! is the lcm of eighteen
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