Answer:
k = -3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define</u>
-9 = k - 6
<u>Step 2: Solve for </u><em><u>k</u></em>
- Add 6 to both sides: -3 = k
- Rewrite: k = -3
Step-by-step explanation:
Nø of sample space, n(s) = 40
nø of unripe oranges, n (u) = 12
no of ripe oranges, n (r) = 40 - 12 = 28
Now
The probability that it is ripe is, P(E)
= n(r) / n(s)
= 28 / 40
= 7 / 10
Also the probability that it is unripe is, P(E)
= n(u) / n(s)
= 12 / 40
= 3 / 10
Hope it will help :)❤
Answer:
b = 40 - p
42b + 52p = 350
Step-by-step explanation:
Given : No. of small blue pom-pom boxes = b
No. of large orange pom-poms = p
cost of 1 box of blue pom pom = $42
cost of one large orange pom-pom box = $52
Solution:
Since we are given that the company has only 40 boxes
⇒b+p=40
⇒b=40-p
Since cost of 1 box of blue pom pom = $42
So, cost of b box of blue pom pom = $42b
Since,cost of one large orange pom-pom box = $52
So,cost of p large orange pom-pom box = $52p
We are also given that the company plan to make $350
⇒42b+52p=350
Hence Option b is correct
b = 40 - p
42b + 52p = 350
Answer:
Step-by-step explanation:
It is given that the snack shop makes 3 mixes of nuts in the following proportions.
Mix I: 6 lbs peanuts, 2 lbs cashews, 2 lbs pecans.
Mix II: 5 lbs peanuts, 3 lbs cashews, 2 lbs pecans.
Mix III: 3 lbs peanuts, 4 lbs cashews, 3 lbs pecans.
they received an order for 25 of mix I, 18 of mix II, and 35 of mix III.
We need to find the matrices A & B for which AB gives the total number of lbs of each nut required to fill the order.
Mix I Mix II Mix III
peanuts 6 5 3
cashews 2 3 4
pecans 2 2 2
The product of both matrices is
Therefore matrix AB gives the total number of lbs of each nut required to fill the order.
What are the numbers x and y are sopposed to be?
