No because you would be dividing the first equation by four, for an example if m=32.5 in the first equation, if you put that into the second equation and divide it by four you won’t get 130 like in the first equation
There is one clock that shows the right time so we do not have to worry about the one which is always correct.
Talking about the second clock that loses a minutes in every 24 hours (or in a day), so after 60 days (since it has lost 60 minutes because it is losing 1 minute everyday) it will show 11:00 a.m when it is exactly the noon.
So this way, in total it will take
days before it shows the correct noon.
Now, the third clock gains a minute every 24 hours (or in a day) , after 60 days (when it has gained 60 minutes or a complete hour) it will show 1:00 p.m when it is exactly the noon.
This way, it will take
days (since it has gained a minute everyday) when it shows the correct noon.
Therefore, it will take 1440 days before all the three clocks show the correct time again.
Its positive for the supermarkets oweners
length of big square

length of small square

difference between length of two square
=5.2-3.5
=1.7
I think I'd be the $40 she charges every hour she works. If this is multiple choice mind drop-in the options