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miskamm [114]
4 years ago
9

Can someone help me with this please?

Mathematics
1 answer:
pantera1 [17]4 years ago
4 0

<em>Answer:</em>

<em>D I believe </em>

<em>explanation: 772.malachi on insta</em>

<em></em>

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Solve the system of equations by finding the reduced row echelon form of the augmented matrix. Write the solutions for x and y i
Gwar [14]

Answer:

The solutions for the given system of equations are:

\left \{ {{x=-5} \atop {y=12-4z}} \right.

Step-by-step explanation:

Given the equation system:

\left \{ {{3x+y+4z=-3} \atop {-x+y+4z=17}} \right.

We obtain the following matrix:

\left[\begin{array}{cccc}3&1&4&-3\\-1&1&4&17\end{array}\right]

<u>Step 1:</u> Multiply the fisrt row by 1/3.

\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\-1&1&4&17\end{array}\right]

<u>Step 2:</u> Sum the first row and the second row.

\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&\frac{4}{3} &\frac{16}{3}&16\end{array}\right]

<u>Step 3:</u> Multiply the second row by 3/4.

\left[\begin{array}{cccc}1&\frac{1}{3} &\frac{4}{3}&-1\\0&1 &4&12\end{array}\right]

<u>Step 4:</u> Multiply the second row by -1/3 and sum the the first row.

\left[\begin{array}{cccc}1&0 &0&-5\\0&1 &4&12\end{array}\right]

The result of the reduced matrix is:

\left \{ {{x=-5} \atop {y+4z=12}} \right.

This is equal to:

\left \{ {{x=-5} \atop {y=12-4z}} \right.

These are the solutions for the system of equations in terms of z, where z can be any number.

6 0
3 years ago
Abram rode in a cab for 9 miles. The taxi driver charged $2.50 for the first z
MAVERICK [17]

Answer:

Abram payed $12.50 for the cab ride in all.

7 0
3 years ago
I NEED HELP WITH 14!!! WRITE IT AS AN INEQUALITY AND SOLVE!! BEST ANSWER GETS BRAINLIEST!! IF U NEED A POINTS BOOST ANSWER THIS
Gwar [14]
17x+22 must be equal or less than 80

17x is equal or less than 58.

X is how many shirts he bought
6 0
3 years ago
Read 2 more answers
May someone help me out with this please
lions [1.4K]
To work out 7% of 600, this is what you do
7/100 x 600 
this will give you your answer 
7% of 600 = 42
7 0
3 years ago
Solve equation, check for extraneous solutions
fiasKO [112]

Start with

1=\dfrac{1}{n^2}+\dfrac{n^2-4n-5}{3n^2}

We observe that both fractions are not defined if n=0. So, we will assume n \neq 0.

We multiply both numerator and denominator of the first fraction by 3 and we sum the two fractions:

1=\dfrac{3}{3n^2}+\dfrac{n^2-4n-5}{3n^2} = \dfrac{n^2-4n-2}{3n^2}

We multiply both sides by 3n^2:

n^2-4n-2=3n^2

We move everything to one side and solve the quadratic equation:

2n^2+4n+2=0 \iff 2(n^2+2n+1)=0 \iff 2(n+1)^2=0 \iff n+1=0 \iff n=-1

We check the solution:

1=\dfrac{1}{1}+\dfrac{1+4-5}{3} \iff 1 = 1+0

which is true

8 0
3 years ago
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