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Komok [63]
3 years ago
9

PLEASE HELP What is the radical form of the expression 423 ? 43−−√ 34−−√ 42−−√3 24−−√3

Mathematics
1 answer:
ira [324]3 years ago
8 0

For this case we must express the number "423" in a radical way.

We have to, we can rewrite it as:

423 = 9 * 47 = 3 ^ 2 * 47

So, we have to:

423 = \sqrt {3 ^ 2 * 47}

By definition of properties of powers and roots we have:

\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}

So:

423 = \sqrt {3 ^ 2 * 47} = 3 \sqrt {47}

Answer:

3 \sqrt {47}

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Someone help me plsss
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Answer:

x= 14 and the angle mesurement is 30

Step-by-step explanation:

Create the formula 60+3x-12=90

Solve for x.

x=14

the plug 14 into 3x-12 to get 30 or you can do 90-60 to get 30 as well.

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The area of a rectangle is 99 square units. Its width measures 9 units. Find the length of its diagonal. Round to the nearest te
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Answer:

14.2

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11^2 + 9^2 =c^2

121 + 81 = c^2

The square root of 202 = c^2

14.2126704=14.2

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8 0
3 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
kow [346]

Answer:

  • f has a maximum in ( (2,0) , 4) and ( (-2,0) , 4)
  • f has a minimum in ( (0,2) , -4 ) and ((0,-2) , -4)

Step-by-step explanation:

f(x,y) = x²-y² and the restriction is

g(x,y) = 4

with g(x,y) = x²+y²

an extreme (x0,y0) of f following that restriction must satisfy

\nabla f (x_0,y_0) = \lambda \nabla g(x_0,y_0)

For ceratin constant λ

Now

\nabla f (x,y) = (2x,-2y)\\\nabla g(x,y) = (2x,2y)

Thus, they are equal in the first coordinate, so in order for them to be proportional one of the following must happen:

  • The second coordinates are equal (this happens only if y=0, because otherwise 2y is not equal to -2y)
  • The first coordinate is 0

So, the critical points have the form (x0,0) and (0,y0), also since they have to fulfill the restriction, we have

x0² + 0² = 4, then x0 = 2 or -2

same with (0,y0)

0²+y0² = 4, then y0 must be 2 or -2

Then the critical points are (2,0), (-2,0), (0,2), (0,-2).

In order to find the extremes now we just have to evaluate in each candidate we have and compare the results

f(2,0) = 2² = 4

f(-2,0) = (-2)² = 4

f(0,2) = 0-2² = -4

f(0,-2) = 0-(-2)² = -4

Thus

  • f has a maximum in ( (2,0) , 4) and ( (-2,0) , 4)
  • f has a minimum in ( (0,2) , -4 ) and ((0,-2) , -4)
4 0
3 years ago
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