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olga2289 [7]
3 years ago
9

Which of the following are properties of a perfect square trinomial?

Mathematics
2 answers:
mario62 [17]3 years ago
8 0

Answer:

neither of the perfect square can have a minus sign

if the perfect square terms are a2 and b2 then the other term must be 2ab or -2ab

Step-by-step explanation:

Idk if this is for apex for you but i just took the quiz amd those were the answers

LiRa [457]3 years ago
7 0

Answer:

give mah a pic

Step-by-step explanation:

You might be interested in
Find the value by evaluating the function. Do not include spaces in your answer.
Mamont248 [21]

Answer:

Solution is 34

Step-by-step explanation:

to find f(8) you plug in 8 for x in the equation

f(x)=4(8)+2=34

hope this helps.

7 0
3 years ago
Why does multiple of 3 add up digits trick work?
kherson [118]
You must be referring to the quick way to determine whether a given integer is divisible by 3; that is, 3 divides an integer x whenever the digits of x sum to a multiple of 3.

Suppose x has n\ge1 digits. We can expand it as a sum of the numbers in any given digits place by the corresponding power of 10. For example, if x=2148, we can write

2148=2\times10^3+1\times10^2+4\times10^1+8\times10^0

More generally, if

x=d_{n-1}d_{n-2}\ldots d_1d_0

(where d_i denotes the numeral in the 10^i-th's place), then we have the expansion

x=d_{n-1}10^{n-1}+d_{n-2}10^{n-2}+\cdots+d_110^1+d_0

Notice that for any integer k, we have

10^k-1=\underbrace{99\ldots99}_{k\text{ 9s}}

which is clearly divisible by 3. So from each power of 10 in the expansion of x, we can add and subtract 1, then rearrange the terms of the sum:

x=d_{n-1}10^{n-1}+\cdots+d_110^1+d_0
x=d_{n-1}(10^{n-1}-1+1)+\cdots+d_1(10^1-1+1)+d_0
x=d_{n-1}(10^{n-1}-1)+\cdots+d_1(10^1-1)+(d_{n-1}+\cdots+d_1+d_0)

We know 10^k-1 is divisible by 3, which means the remainder upon dividing x by 3 is just the sum of the digits of x. If this remainder is divisible by 3, then so must be the original number, x.

Back to our previous example: if x=2148, then we have the expansion

2148=2\times10^3+10^2+4\times10+8
2148=2(999+1)+(99+1)+4(9+1)+8
2148=2\times999+99+4\times9+(2+1+4+8)

Dividing through by 3, we get a remainder of 2+1+4+8=15, which is divisible by 3, and so 2148 must also be a multiple of 3.

In case for some reason you're not convinced 15 is a multiple of 3, you can apply the same trick:

15=10+5
15=9+1+5

Dividing through by 3 leaves a remainder of 1+5=6, which is also a multiple of 3, so that 15 must be, too.
7 0
3 years ago
If 3 apples cost $6 how much would 1 Apple cost
AnnyKZ [126]
Divide 6 by 3
3 goes into 6, 2 times so one apple costs $2
8 0
3 years ago
Read 2 more answers
How can you use unit rates in multiplication to solve for missing measures and equivalent ratio problems?
vodka [1.7K]
By viewing equivalent ratios and rates as deriving from, and extending, pairs of rows (or columns) in the multiplication table and by analyzing simple drawings that indicate the relative size of quantities.
4 0
3 years ago
Easy question easy points yall :p
yarga [219]

Answer:

+or- 8

Step-by-step explanation:

take the square root of 64

8 0
3 years ago
Read 2 more answers
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