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olga2289 [7]
2 years ago
9

Which of the following are properties of a perfect square trinomial?

Mathematics
2 answers:
mario62 [17]2 years ago
8 0

Answer:

neither of the perfect square can have a minus sign

if the perfect square terms are a2 and b2 then the other term must be 2ab or -2ab

Step-by-step explanation:

Idk if this is for apex for you but i just took the quiz amd those were the answers

LiRa [457]2 years ago
7 0

Answer:

give mah a pic

Step-by-step explanation:

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Whats 926 divided by 30
balandron [24]

30.87 ✅

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

\frac{926}{30}  \\  = 30 \frac{26}{30}  \\ ( \: or \: ) \\  = 30.8666 \\  = 30.87

\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}

4 0
2 years ago
Help pleaseeeee ???????
Mkey [24]

Answer: y+6x = -34

<em><u>Step-by-step explanation:</u></em>

y-2= -6(x+6)                              (<u><em>Ax+By=C is the goal)</em></u>

y-2= -6x-36  <u>(-6) x & (-6) 6</u>

y=-6x-34 (Add 2 to both sides)

<em>y+6x = -34   [Add 6x to both sides]</em>

5 0
2 years ago
What should you do if in the REVIEW phase of problem solving, you find the answer doesn't make sense?
N76 [4]

Answer:

I would recheck the answer

Step-by-step explanation:

there is my opinion :)

4 0
3 years ago
Find the particular solution that satisfies the differential equation and the initial condition.
Vesnalui [34]

Answer:

1) y =4x^2 +7

2) y =7s^2 -3s^4 +181

Step-by-step explanation:

Assuming that our function is y = f(x) for the first case and y=f(s) for the second case.

Part 1

We can rewrite the expression like this:

\frac{dy}{dx} =8x

And we can reorder the terms like this:

dy = 8 x dx

Now if we apply integral in both sides we got:

\int dy = 8 \int x dx

And after do the integrals we got:

y = 4x^2 +c

Now we can use the initial condition y(0) =7

7 = 4(0)^2 +c, c=7

And the final solution would be:

y =4x^2 +7

Part 2

We can rewrite the expression like this:

\frac{dy}{ds} =14s -12s^3

And we can reorder the terms like this:

dy = 14s -12s^3 dx

Now if we apply integral in both sides we got:

\int dy = \int 14s -12s^3 ds

And after do the integrals we got:

y = 7s^2 -3s^4 +c

Now we can use the initial condition y(3) =1

1 = 7(3)^2 -3(3)^4 +c, c=1-63+243=181

And the final solution would be:

y =7s^2 -3s^4 +181

7 0
3 years ago
PLEASE HELP WILL MARK YOU AS BRAINLIEST​
Alenkasestr [34]
I want to help, but I’m not seeing a question though.
4 0
2 years ago
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