In this situation, choose length and width such that 12.75=l*w. writing it as a mixed number you have 51/4=sqrt51/2*sqrt51/2 or any other combination you can use.
Let a = 693, b = 567 and c = 441
Now first we will find HCF of 693 and 567 by using Euclid’s division algorithm as under
693 = 567 x 1 + 126
567 = 126 x 4 + 63
126 = 63 x 2 + 0
Hence, HCF of 693 and 567 is 63
Now we will find HCF of third number i.e., 441 with 63 So by Euclid’s division alogorithm for 441 and 63
441 = 63 x 7+0
=> HCF of 441 and 63 is 63.
Hence, HCF of 441, 567 and 693 is 63.
Answer:
x=4
Step-by-step explanation:
Answer:
x<2
Step-by-step explanation:
-x>-2
x<2
It's the explanation
Answer:
where are the ordered pairs
Step-by-step explanation:
