The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
Answer:
B
Step-by-step explanation:
Answer:
Raise the power
Step-by-step explanation:
| shade | | | Each rectangle stands for one third so shade
| this | | | only one rectangle.
| one | | | And one rectangle has two books in it (you
| | | | divide 6 by 3 to get 2).
| | | |
| | | |
| | | |
R = -1/10x. Don't forget to rate and give me the brainliest answer! Then, I can help you with all your problems! ^-^ ~