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Julli [10]
3 years ago
11

Find b and then solve the equation: 2x^2+bx−10=0, if one of its roots is 5

Mathematics
2 answers:
cestrela7 [59]3 years ago
5 0

Answer:

the b value is -8, i just had this problem in my hw, and the value is -8 because the value of c will be equal to -b x a; it seems the other guy forgot the negative.

Step-by-step explanation:

slavikrds [6]3 years ago
4 0

Vietas formula tells us that the product of our two roots is equal to the constant term of a quadratic over the leading coefficient, so:

[tex] r_1r_2=-\frac{-10}{2} \implies 5*r_1=-5 \implies r_1=-1[\tex]

It also tells us that the b term in our quadratic is equal to the negative of the sum of the terms divided by the leading coefficient, so:

[tex] r_1+r_2=-\frac{b}{2} \implies 4=-\frac{b}{2} \implies b=-8 [\tex]

So, one of our roots is 5, the other is -1, and our b value is 8.

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IrinaVladis [17]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
70 POINTS!
siniylev [52]
You can solve this question with pythagorean theorem > {a}^{2} + {b}^{2} = c^{2}

Based on the information, you already have one side (a or b, doesn't matter, 12) and the hypotenuse (the cut, c, 15)

So: 
1. 12^{2} + b^{2} = 15^{2}
2. 144+b^{2} = 225
3. b^{2} = 225 - 144 = 81
4. b=  \sqrt{81}
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7 0
3 years ago
I need help with 6 & 8
zimovet [89]
1. We need to get rid of those pesky parentheses. We do this by distributing the 3.

2. We need to get "n" by itself, so we add 9 to both sides.

3. Add like terms.

4. Now, we need to get rid of the -9, so we divide both sides by -9. Remember that dividing by negative numbers changes the direction of the "greater than or equal to" symbol.

5. We divide, and the negatives cancel.

I wrote the answer both ways so that I could tell what the number line needed to look like.

7 0
3 years ago
What is the y -value of the vertex of 4x^2 + 8X -8?
Aleksandr-060686 [28]

Answer:

-12

Step-by-step explanation:

5 0
3 years ago
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MA_775_DIABLO [31]
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You can simplify it even further
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3 years ago
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