Total investment = $10,500
Let x = amount of first investment, and y the amount of the second investment.
First investment:
Interest rate = 9 (1/5)% = 0.092
Earned interest = 0.092x
Second investment:
Interest rate = 9% = 0.09
Earned interest = 0.09y
Total interest after one year is $957.00, therefore
0.092x + 0.09y = 957
or
1.0222x + y = 10633.33 (1)
Also,
x + y = 10500 (2)
Subtract (2) from (1).
0.0222x = 133.33
x = 6000
y = 10500 - x = 4500
Answer:
The first investment is $6,000 at 9 (1/5)% rate;
The second investment is $4,500 at 9% rate.
Answer:
A≈1017.88 if r=18m or A≈254.47 if r=9
Step-by-step explanation:
A=Pi*r^2, plugging in 18 m or 9 m since lack of info but i assume you are giving 18m total length of circle, gives us answer.
Answer:
what you mean
Step-by-step explanation:
8,000,000 + 200,000 + 5,000
Answer:
C
Step-by-step explanation:
