Heres a photo of the solution
Please brainlist, thanks.
Answer:
Step-by-step explanation:
From the information given,
Number of personnel sampled, n = 85
Mean or average = 6.5
Standard deviation of the sample = 1.7
We want to determine the confidence interval for the mean number of years that personnel spent in a particular job before being promoted.
For a 95% confidence interval, the confidence level is 1.96. This is the z value and it is determined from the normal distribution table. We will apply the following formula to determine the confidence interval.
z×standard deviation/√n
= 1.96 × 6.5/√85
= 1.38
The confidence interval for the mean number of years spent before promotion is
The lower end of the interval is 6.5 - 1.38 = 5.12 years
The upper end is 6.5 + 1.38 = 7.88 years
Therefore, with 95% confidence interval, the mean number of years spent before being promoted is between 5.12 years and 7.88 years
I think there is only one point x = -1.
Are you sure it's not x^2 + 1 = 0, if you had this equation the two points will be -1 and 1.
Or the equation was something like: x+1 =y?
If the equation is x+1=y.
First point: (-1,0)
Second point: (0,1)
//Hope this is what you are looking for. Sorry if it's incorrect.
I think you'r right but I cant see the quitction
The equation is 2(-2+x)=y and result is 9 less than the number
So the answer is 2(-2+x)=y-9