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BlackZzzverrR [31]
4 years ago
8

Solve for k m=-8j-9k+9

Mathematics
2 answers:
fomenos4 years ago
8 0
M = -8j - 9k + 9....solving for k

m + 8j - 9 = -9k
(m + 8j - 9 ) / -9 = k OR -m/9 - 8/9j + 1 = k
Delvig [45]4 years ago
4 0
M=-1


I think I'm sorry if it isn't right
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You can add or multiply regardless of how the numbers are grouped.
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Given ƒ(x) = 8x + 25, find x when ƒ(x) = 9.
liubo4ka [24]

Answer:

x=  -2

Step-by-step explanation:

f(x) is the same thing as y so just subtract 25 and divide by 8.

8 0
4 years ago
Which of the following best describes a consumer?
Margarita [4]

Answer:  Second option is correct.

Step-by-step explanation:

Since we have ask that

Consumer refers to those person who used to consume things like purchase goods and services for personal use.

Someone who studies economics are known as economists they are not consumers, they are known for their study of economics.

A business owner who sells clothes can be known as traders or merchants or business man but they do not consider as consumers as they don't buy goods and services but they provide all of these.

A farmer who sells his crops are known as producers instead of consumers.

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7 0
4 years ago
Read 2 more answers
Simplify 5x5^2 leaving your answer in index form
Gemiola [76]

Answer:

125 should be the answer

4 0
3 years ago
PLEASE HELP!!!!
Tasya [4]

Answer:

y = g(x) = 1 +  x

Now, the range of a function is the set of the possible values of y.

In this function, a linear function, y can be any real number, so the range of this function is { y ∈ ℝ )

y = h(x) = x^2 + 2*x

This is a quadratic function, as the leading coefficient is positive, we know that the arms of the function go up.

For a quadratic function y = a*x^2 + b*x + c

The minimum is at:

x = -b/2a.

In this case, b = 2 and 1 = 1

the minimum is at:

x = -2/2 = -1

The minimum is:

y = h(-1) = 1^2 +2*(-1) = -1

Then the range of this function is

{y ∈ ℝ ≥ -1 )

The composite functions are:

g∘h = g(h(x)) = 1 + x^2 + 2*x

The minimum is still at x = -1

g∘h(-1) = 1 + -1^2 + 2*-1 = 0

Then the range of this function is:

{y ∈ ℝ ≥ 0 )

The other composition is:

h∘g = h(g(x)) =  (1 + x)^2 + 2*(1 + x) = 1 + 2*x + x^2 + 2 + 2*x

h∘g = x^2 + 4*x + 3

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x = -4/2*1 = -2

h∘g(-2) = (-2)^2 + 4*-2 + 3 = 4 - 8 + 3 = -1

The range is:

{y ∈ ℝ ≥ -1 )

5 0
3 years ago
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