Answer:
:v mira tu que cosas de la vida
L=W-2LW=35 substitute in W-2 for L(W-2)(W)=35W2 -2w -35=0(W-5)(W-7)=0therefore w=7 and L=5
1. Find the H.C.F. of 4x2y3 and 6xy2z.
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2