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daser333 [38]
3 years ago
10

How many triangles can be constructed with sides measuring 7 cm, 6 cm, and 9 cm? more than one one none

Mathematics
1 answer:
REY [17]3 years ago
3 0

Answer:

none

Step-by-step explanation:


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JK Rowling is autographing some of the new Harry Potter books.A store sells 56 books and she is able to autograph 5/8 of the boo
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56/8 = 7
7x5 = 35 books
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The first song performed during a concert was more than 60 seconds longer than the final song. The first song was 190 seconds lo
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Answer:

3. 130

2. Open Circle at f, shaded left.

Step-by-step explanation:

Edg. 2020

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4 years ago
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Choose the correct equation of the line with the given slope and y-intercept. m = 1, b = 4
vredina [299]
It's D y = x + 4, use y=mx+b
5 0
3 years ago
Find the measure of each angle :Supplementary angles with measures (2x+4) and (3x+1)
denpristay [2]
First of all, we need to know what is supplementary angle is. It's means that two angles add together to get 180° angle. For examples, 135° and 45° angles add together called supplemtary angles.
Now, we know Supplementary angles with measures (2x+4) and (3x+1), so
(2x+4)+(3x+1)=180
2x+4+3x+1=180
Combining like terms
2x+3x+4+1=180
5x+5=180
Subtract 5 to each side
5x+5-5=180-5
5x=175
Divided 5 to each side
5x/5=175/5
x=35°
Next, find the measure of two angles by substitute x=35° with (2x+4) and (3x+1), so
2x+4
=2(35)+4
=70+4
=74°

(3x+1)
=3x+1
=3(35)+1
=105+1
=106°. As a result, the two supplementary angle are 106° and 74°. Hope it help!
4 0
3 years ago
Read 2 more answers
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Darina [25.2K]

Answer:

Given definite  integral as a limit of Riemann sums is:

\lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Step-by-step explanation:

Given definite integral is:

\int\limits^7_4 {\frac{x}{2}+x^{3}} \, dx \\f(x)=\frac{x}{2}+x^{3}---(1)\\\Delta x=\frac{b-a}{n}\\\\\Delta x=\frac{7-4}{n}=\frac{3}{n}\\\\x_{i}=a+\Delta xi\\a= Lower Limit=4\\\implies x_{i}=4+\frac{3}{n}i---(2)\\\\then\\f(x_{i})=\frac{x_{i}}{2}+x_{i}^{3}

Substituting (2) in above

f(x_{i})=\frac{1}{2}(4+\frac{3}{n}i)+(4+\frac{3}{n}i)^{3}\\\\f(x_{i})=(2+\frac{3}{2n}i)+(64+\frac{27}{n^{3}}i^{3}+3(16)\frac{3}{n}i+3(4)\frac{9}{n^{2}}i^{2})\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{3}{2n}i+\frac{144}{n}i+66\\\\f(x_{i})=\frac{27}{n^{3}}i^{3}+\frac{108}{n^{2}}i^{2}+\frac{291}{2n}i+66\\\\f(x_{i})=3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

Riemann sum is:

= \lim_{n \to \infty} \sum^{n} _{i=1}3[\frac{9}{n^{3}}i^{3}+\frac{36}{n^{2}}i^{2}+\frac{97}{2n}i+22]

4 0
3 years ago
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