Find the locus of a point P such that its ordinate is equal to the abscissa. Hence required equation of the locus of point P is y = 5x + 9. Hence required equation of the locus of point P is x = 2y + 3.
Hi,
f(1)=16
f(2)=f(1)+2*2=16+4=20
f(3)=f(2)+2*3=20+6=26
f(4)=f(3)+2*4=26+8=34
When you set

, you end up with the differentials

. Multiplying both sides by 2 gives

.
Then the integral is
Answer : 9
Step-by-step explanation:
The answer is 9 because a constant is a number on its own, or sometimes a letter such as a, b or c to stand for a fixed number.