Question

17. Which of the following equations would graph a line parallel to 3y = x + 5? (

Answer 1

The equation 3y = x + 1 would graph a line parallel to 3y = x + 5 ⇒ 1st

Step-by-step explanation:

Parallel lines have same slopes and different y-intercepts

To find which equation would graph a line parallel to 3y = x + 5

1. Put the equation in the form of y = mx + c

2. m is the slope of the line and c is the y-intercept

3. Look for the equation which has the same values of m and different

   values of c

∵ 3y = x + 5

- Divide each term of the equation by 3 to put the equation in the

 form of y = mx + c

∴ y = $\frac{1}{3}$ x + $\frac{5}{3}$

∴ m = $\frac{1}{3}$

∴ c = $\frac{5}{3}$

The first answer:

∵ 3y = x + 1

- Divide each term of the equation by 3

∴ y = $\frac{1}{3}$ x + $\frac{1}{3}$

∴ m = $\frac{1}{3}$

∴ c = $\frac{1}{3}$

∵ The two equations have same slope m = $\frac{1}{3}$

∵ The two equations have different y-intercepts c = $\frac{5}{3}$

   and c = $\frac{1}{3}$

∴ 3y = x + 5 and 3y = x + 1 represent two parallel lines

The equation 3y = x + 1 would graph a line parallel to 3y = x + 5

Learn more:

You can learn more about slope of a line in brainly.com/question/12954015

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