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3 years ago

What is 10 hours divided into $160?

Mathematics

2 answers:

sertanlavr [38]3 years ago

4 0

$16 per hour. You just divide 160 by 10, or a quicker way would be to take the zero off of the $160.

astra-53 [7]3 years ago

3 0

160/10 =16 dollars per hour

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Which of the following fractions can be represented by a terminating decimal? OA 8/9 OB)13/8 OC) 4/3 OD) 6/11

velikii [3]

Answer:

$\frac{13}{8}$

Step-by-step explanation:

$\frac{13}{8} \: \: cuz \: when \: u \: simplify \: into \: a \: decimal \: would \: be \: 1.625 \\ and \: if \: u \: round \: would \: be \: 2 \: so \: u \: take \: out \: the \: decimal \:$

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3 years ago

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Which solid figure has one polygon base?

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Q1: The answer is A. pyramid.
A pyramid has one polygon base. A prism has two polygon bases. A cone has one circular base. A cylinder has two circular bases.

Q6: The answer is false.
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A = 2(wl + hl + hw)
A1 = 2(4*5 + 6*5 + 6*4) = 2(20+30+24) = 2*74 = 148
A2 = 2(6*4 + 5*4 + 5*6) = 2(24+20+30) = 2*74 = 148

Q7. The answer is A. 6 feet
The volume of rectangular prism is:
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w = ?
So, just replace the knowing facts:
288 = w * 8 * 6
288 = w * 48
w = 288/48 = 6

Q8: The answer is 216 ft³
The volume of the cube is:
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3 years ago

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-2(x + 6) = 5x - 10

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The Answer: x = -2/7

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3 years ago

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1. P(getting all head)= $\frac{n(getting-all-head)}{n(Sample-space)}$

2. Event: getting all head can happen in only one way: HHH

3. n(Sample space) can be calculated by

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3 years ago

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One card is drawn at random from a deck of 52 cards. The first card is not replaced, and a second card is drawn. (Enter your pro

andriy [413]

Answer:

We have a 52 card deck:

a. Find the probability that both cards are clubs.

The probability of drawing a club will be equal to the quotient between the number of clubs in the deck divided by the total number of cards in the deck.

We initially have 13 clubs and 52 cards, then the probability of drawing a club in the first draw is:

p1 = 13/52.

Now the probability of drawing a club in the second draw will be:

p2 = 12/51

Where each number is decreased by one because we already drew a card, and that card was a club.

Then the probability of both events happening will be equal to the product of the individual probabilities:

P = p1*p2 = (13/52)*( 12/51) = 0.059

b. Find the probability that the first card is a spade and the second is a club.

Same as before, the probability of first drawing a spade is:

p1 = 13/52

And the probability of drawing a club in the second draw will be:

p2 = 13/51

This case differs from the prior one because for the second draw we have 13 clubs in the deck, and as we already drew one card (that was not a club) the total number of cards in the deck is 51.

Now the joint probability will be:

P = p1*p2 = (13/52)*(13/51) = 0.064

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