Answer:
Step-by-step explanation:a = m + (p-1)*d
b = m + (q-1)*d
c = m + (r-1)*d
p(b-c) = p*(q-r)*d
q(c-a) = q*(r-p)*d
r(a-b) = r*(p-q)*d
p(b-c)+q(c-a)+r(a-b)
= p*(q-r)*d + q*(r-p)*d +r*(p-q)*d
= (pq-pr+qr-pq+rp-qr)*d
= 0*d = 0
So i prove p(b-c)+q(c-a)+r(a-b)=0 hope this is helpfull
10 separated into 5 groups is 10/5
5 goes into 10 2 times.
10/5=2
C=A+B
C₄₁= row=4; column=1
C₄₁=A₄₁+B₄₁
=2(7)-3(4)
=14-12
=2
Answer: C₄₁=2
