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3 years ago

Solve the equation. d3 = 64

Mathematics

2 answers:

marissa [1.9K]3 years ago

6 0

3d/3 =64/3
I think the answer is 21.3

cricket20 [7]3 years ago

5 0

Answer:

65D

Step-by-step explanation:

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3 years ago

I need to know which number is greater on each problem from numbers 8-12 and 13-16

Elena L [17]

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4 years ago

The average value of a function f over the interval [−1,2] is −4, and the average value of f over the interval [2,7] is 8. What

Anna71 [15]

The average value of a continuous function f(x) over an interval [a, b] is

$\displaystyle f_{\mathrm{ave}[a,b]} = \frac1{b-a}\int_a^b f(x)\,dx$

We're given that

$\displaystyle f_{\rm ave[-1,2]} = \frac13 \int_{-1}^2 f(x) \, dx = -4$

$\displaystyle f_{\rm ave[2,7]} = \frac15 \int_2^7 f(x) \, dx = 8$

and we want to determine

$\displaystyle f_{\rm ave[-1,7]} = \frac18 \int_{-1}^7 f(x) \, dx$

By the additive property of definite integration, we have

$\displaystyle \int_{-1}^7 f(x) \, dx = \int_{-1}^2 f(x)\,dx + \int_2^7 f(x)\,dx$

so it follows that

$\displaystyle f_{\rm ave[-1,7]} = \frac18 \left(\int_{-1}^2 f(x)\,dx + \int_2^7 f(x)\,dx\right)$

$\displaystyle f_{\rm ave[-1,7]} = \frac18 \left(3\times(-4) + 5\times8\right)$

$\displaystyle f_{\rm ave[-1,7]} = \boxed{\frac72}$

7 0

3 years ago

What is the answer to 3 + y; 1/3 (6+y)

baherus [9]

Answer:

No, the expression are not equivalent.

Step-by-step explanation:

No way to simplify 3 + y so we leave it as is. Let's look at $\frac{1}{3}\left(6+y\right)$

If we expand using distributive property we get:

$2+\frac{y}{3}$

3 + y does not equal to 2 + y/3.

5 0

3 years ago

What two numbers have an absolute value of 21.63

Mazyrski [523]

The correct answer would be -21.63 and +21.63

7 0

3 years ago