If a cylinder’s radius and height are each shrunk down to a third of the original size, what would be the formula to find the mo
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Answer:
Step-by-step explanation:
Note: I will leave the answers as fraction and in terms of pi unless the question states rounding conditions to ensure maximum precision.
From the question, we can tell it is a inversed-cone (upside down)
Volume of Cone =
a) Given Diameter , d = 15.5cm and Length , h = 350cm,
we first find the radius.
We will now find the volume of the cone.
Volume of cone
We know the density of ice is 0.93 grams per
(Nearest Gram)
b) After 1 hour, we know that the new radius = 7.75cm - 0.35cm = 7.4cm
and the new length, h = 350cm - 15cm = 335cm
Now we will find the volume of this newly-shaped cone.
Volume of cone =
Volume of cone being melted = New Volume - Original volume
=
c) Lets take the bucket as a round cylinder.
Given radius of bucket, r = 12.5cm (Half of Diameter) and h , height = 30cm.
Volume of cylinder =
To overflow the bucket, the volume of ice melted must be more than the bucket volume.
Volume of ice melted after 5 hours =
See, from here of course you are unable to tell whether the bucket will overflow as all are in fractions, but fret not, we can just find the difference.
Volume of bucket - Volume of ice melted after 5 hours
=
from we can see the bucket can still hold more melted ice even after 5 hours therefore it will not overflow.