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Leno4ka [110]
3 years ago
13

What is the name of the property given below ? If ab = 0 then a = 0 , b = 0 or both a = 0 and b = 0 . A. Zero property B. Distri

butive property O C. Zero product rule D. Commutative property
Mathematics
1 answer:
FromTheMoon [43]3 years ago
3 0

Answer:

c. zero product rule

Step-by-step explanation:

apex

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(-3,2)

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A certain threethree​-cylinder combination lock has 6060 numbers on it. To open​ it, you turn to a number on the first​ cylinder
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9,150,625.

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Write a rule for the nth term of the arithmetic sequence 3, 11, 19, 27, 35... what is a20?
vladimir1956 [14]
3, 11, 19, 27, 35...

a = 3
d = 11-3 = 8
a20 = a + 19d = 3 + 19*8 = 3 + 132 = 135

HOPE IT HELPS!
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3 years ago
Please helpppppppp<br><br> If you don’t know it don’t answer please
vladimir2022 [97]

Answer:

x=36

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Step-by-step explanation:

I didnt do this type of problem in a while but Im pretty sure its correct

6 0
3 years ago
Which equation is y = –6x^2 + 3x + 2 rewritten in vertex form? y = negative 6 (x minus 1) squared + 8 y = negative 6 (x + one-fo
mart [117]

Answer:

y  = -6(x - \frac{1}{2})^2 -\frac{7}{2}

Step-by-step explanation:

Given:

y = -6x^2 + 3x + 2

Required

Rewrite in vertex form

The vertex form of an equation is in form of: y = a(x - h)^2+ k

Solving: y = -6x^2 + 3x + 2

Subtract 2 from both sides

y - 2 = -6x^2 + 3x + 2 - 2

y - 2 = -6x^2 + 3x

Factorize expression on the right hand side by dividing through by the coefficient of x²

y - 2 = -6(x^2 + \frac{3x}{-6})

y - 2 = -6(x^2 - \frac{3x}{6})

y - 2 = -6(x^2 - \frac{x}{2})

Get a perfect square of coefficient of x; then add to both sides

------------------------------------------------------------------------------------

<em>Rough work</em>

The coefficient of x is \frac{-1}{2}

It's square is (\frac{-1}{2})^2 = \frac{1}{4}

Adding inside the bracket of -6(x^2 - \frac{x}{2}) to give: -6(x^2 - \frac{x}{2} + \frac{1}{4})

To balance the equation, the same expression must be added to the other side of the equation;

Equivalent expression is: -6(\frac{1}{4})

------------------------------------------------------------------------------------

The expression becomes

y - 2 -6(\frac{1}{4})= -6(x^2 - \frac{x}{2} + \frac{1}{4})

y - 2 -\frac{6}{4}= -6(x^2 - \frac{x}{2} + \frac{1}{4})

y - 2 -\frac{3}{2}= -6(x^2 - \frac{x}{2} + \frac{1}{4})

Factorize the expression on the right hand side

y - 2 -\frac{3}{2}= -6(x - \frac{1}{2})^2

y - (2 +\frac{3}{2})= -6(x - \frac{1}{2})^2

y - (\frac{4+3}{2})= -6(x - \frac{1}{2})^2

y - (\frac{7}{2})= -6(x - \frac{1}{2})^2

y  +\frac{7}{2} = -6(x - \frac{1}{2})^2

Make y the subject of formula

y  = -6(x - \frac{1}{2})^2 -\frac{7}{2}

<em>Solved</em>

7 0
4 years ago
Read 2 more answers
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