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Sergeeva-Olga [200]

4 years ago

10

PLEASE HELP! A city has a population of 390,000 people. Suppose that each year the population grows by 6.25%. What will the popu

lation be after 6 years?
Round your answer to the nearest whole number.

1 answer:

Vaselesa [24]4 years ago

5 0

Answer: The population will be 536,250 people

Step-by-step explanation:

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Alia buys three erasers that cost $0.50 each, two notebooks that cost $5.00 each, and six pencils that cost $0.75 each. Which ex

elixir [45]

The answer is C. because 3(0.50) is $1.50 which equals the erasers price. then two notebooks are $5 each add up to $10. So 2(5). then last 6(0.75) is $4.5 which is the same as the price of six pencils.

3 0

3 years ago

Huck and Jim are waiting for a raft. The number of rafts floating by over intervals of time is a Poisson process with a rate of

Harrizon [31]

Answer: 0.0081

Step-by-step explanation:

Let X be the number of rafts.

Given : The mean number of rafts floating : $\lambda=0.4$ rafts per day .

Then , for 7 days the number of rafts = $\lambda_1=\lambda\times 7=0.4\times7=2.8$ rafts per day .

The formula to calculate the Poisson distribution is given by :_

$P(X=x)=\dfrac{e^{-\lambda_1}\lambda_1^x}{x!}$

Now, the probability that they will have to wait more than a week is given by :-

$P(X>7)=1-P(X\leq7)\\\\=1-(P(0)+P(1)+P(2)+P(3)+P(4)+P(5)+P(5)+P(6)+P(7))\\\\=1-(\dfrac{e^{-2.8}2.8^{0}}{0!}+\dfrac{e^{-2.8}2.8^{1}}{1!}+\dfrac{e^{-2.8}2.8^{2}}{2!}+\dfrac{e^{-2.8}2.8^{3}}{3!}+\dfrac{e^{-2.8}2.8^{4}}{4!}+\dfrac{e^{-2.8}2.8^{5}}{5!}+\dfrac{e^{-2.8}2.8^{6}}{6!}+\dfrac{e^{-2.8}2.8^{7}}{7!})\\\\=1-0.991869258012=0.008130741988\approx0.0081$

Hence, the required probability : 0.0081

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3 years ago

Pls help pls help pls help

Yakvenalex [24]

3 is the correct answer Finn he is corn

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3 years ago

Who can follow me on RBX MY USER IS....XXXLAMBOKID <br> \<br> PLS IM TRYING TO GET LOT OF FOLLOWS

Kaylis [27]

Answer:

I will!!!!!!

Step-by-step explanation:

ok

5 0

3 years ago

Read 2 more answers

Factor 64 - P.<br> (8 - x(8 - x)<br> (8 + x (8 - x)<br> (X + 8)(x-8)

muminat

Question:

Factor $64-x^2$

(8 - x)(8 - x)

(8 + x) (8 - x)

(X + 8)(x-8)

Answer:

Option B: $(8+x)(8-x)$ is the factor

Explanation:

Given that the expression is $64-x^2$

We need to find the factor of the given expression.

Let us rewrite the expression as $8^2-x^{2}$

Since the expression is of the form $a^2-b^2$ , let us use the identity $a^2-b^2=(a+b)(a-b)$

where a = 8 and b = x

Substituting the values in the identity, then the expression can be written as

$8^2-x^{2}=(8+x)(8-x)$

Thus, the factor of the expression is $(8+x)(8-x)$

Hence, Option B is the correct answer.

4 0

3 years ago