If I subtract the square root of 10 and -4, my answer will be

Exspress the ratio from the simplest form 72:36

Vedmedyk [2.9K]

First, find the GCF. For these two numbers, it is 36. (Because 36 times 1 is 36 and 36 times 2 is 72)
Divide both sides by this, which gives you a
2:1 ratio

8 0

2 years ago

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A rectangular swimming pool that is 10 ft wide by 16 ft long is surrounded by a cement sidewalk of uniform width. If the area of

Alchen [17]

We are asked to solve for the width "x" in the given problem. To visualize the problem, see attached drawing.
We have the area of the swimming pool such as:
Area SP = l x w
Area SP = 10 * 16
Area SP = 160 feet2
Area of the swimming pool plus the sidewalk with uniform width:
Area SP + SW = (10 + x) * (16 + x)
160 + 155 = 160 + 10x + 16x + x2
160 -160 + 155 = 26x + x2
155 = 26 x + x2
x2 + 26x -155= 0
Solving for x, we need to use quadratic formula and the answer is 5 feet.

The value of x is <span>5 feet. </span>

5 0

3 years ago

What is the volume of this shape?

jenyasd209 [6]

Answer:
600 ft cubed
Step-by-step explanation:
Triangle volume formula V = 1/2(l*w*h)
1/2(4*12*9) = 216 ft cubed

Formula for rectangular prism V = (l*w*h)
(4*16*6) = 384 ft cubed

Adding the values: 600 ft

6 0

2 years ago

the measurements of a photo and it's frame are shown in the diagram. Write a polynomial that represents the width of the photo.

suter [353]

Answer:

The width of the photo is $4w^2+6w+4$ .

Step-by-step explanation:

From the given figure it is notices that the total width of the frame is

$6w^2+8$

The photo is covered by a frame border and the width of the border is

$w^2-3w+2$

To find the width of the photo we have to subtract the width of upper frame border and lower frame border from the total width of frame.

Width of the photo is

$\text{Width of the photo}=\text{Width of the frame}-2(\text{Width of the frame border})$

$\text{Width of the photo}=6w^2+8-2(w^2-3w+2)$

$\text{Width of the photo}=6w^2+8-2w^2+6w-4$

$\text{Width of the photo}=4w^2+6w+4$

Therefore the width of the photo is $4w^2+6w+4$ .

4 0

2 years ago

Find one value of x that is a solution to the equation:<br>(x^2– 8)^2 + x^2 – 8 = 20<br>x=

Kipish [7]

Answer:

x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

Step-by-step explanation:

Solve for x:

-8 + x^2 + (x^2 - 8)^2 = 20

Expand out terms of the left hand side:

x^4 - 15 x^2 + 56 = 20

Subtract 20 from both sides:

x^4 - 15 x^2 + 36 = 0

Substitute y = x^2:

y^2 - 15 y + 36 = 0

The left hand side factors into a product with two terms:

(y - 12) (y - 3) = 0

Split into two equations:

y - 12 = 0 or y - 3 = 0

Add 12 to both sides:

y = 12 or y - 3 = 0

Substitute back for y = x^2:

x^2 = 12 or y - 3 = 0

Take the square root of both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y - 3 = 0

Add 3 to both sides:

x = 2 sqrt(3) or x = -2 sqrt(3) or y = 3

Substitute back for y = x^2:

x = 2 sqrt(3) or x = -2 sqrt(3) or x^2 = 3

Take the square root of both sides:

Answer: x = 2 sqrt(3) or x = -2 sqrt(3) or x = sqrt(3) or x = -sqrt(3)

8 0

3 years ago