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3 years ago

13

I need help in this asap please

1 answer:

Andre45 [30]3 years ago

6 0

Do u still need the answer its been a week now!

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accoridng to byu idaho entorllemtn statistic there are 12000 femailes student here on camputes during any given semster of those

nordsb [41]

Answer:

so this as a fraction is 3500/12000 which is equivalent to

0.29166666666 we multiply this by 100

29.166666666

so about 29.1% or the students are female and have served a mission

Hope This Helps!!!

4 0

3 years ago

What is the answer to this math equation(x+5)(x²-3x)

Nikolay [14]

Answer:

$x=-5\\x=0\\x=3$

Step-by-step explanation:

I assume your equation to solve is

$(x+5)(x^2-3x)=0$

When we have a product of two factors equal to zero,

$A\cdot B = 0$

The solution is either A = 0 or B = 0.

In this case, this means that we can break the equation into two equations:

$x+5=0\\x^2-3x=0$

Solving the first one, we get:

$x+5=0 \rightarrow x = -5$

For the second one, we rewrite it as:

$x^2-3x=0\\x(x-3)=0$

And we see that this equation has two solutions:

$x=0\\x=3$

Therefore, the three solutions are:

$x=-5\\x=0\\x=3$

8 0

3 years ago

Please help me I really need it in the next 2 mins first and correct answer gets brainly.est

WITCHER [35]

13 units because 7 + 6 = 13

3 0

3 years ago

Read 2 more answers

90 POINTS!!!!! Given: KLIJ inscr. in k(O),m∠K = 64°, measure of arc LI = 69°, measure of arc IJ = 59°, measure of arc KJ =97°

Kay [80]

In any cyclic quadrilateral, angles opposite one another are supplementary, meaning

$m\angle K+m\angle I=m\angle L+m\angle J=180^\circ$

and given that $\boxed{m\angle K=64^\circ}$ , we have $\boxed{m\angle I=116^\circ}$ .

By the inscribed angle theorem,

$m\angle JLK=\dfrac12m\widehat{KJ}$

$m\angle ILJ=\dfrac12m\widehat{IJ}$

and since

$m\angle L=m\angle JLK+m\angle ILJ$

we have

$m\angle L=\dfrac{97^\circ+59^\circ}2\implies\boxed{m\angle L=78^\circ}$

and it follows that

$m\angle J=180^\circ-m\angle L\implies\boxed{m\angle J=102^\circ}$

5 0

3 years ago

Find the value of x. Round your answer to the nearest tenth

Sati [7]

$x=13.8$

<u><em>Step-by-step explanation:</em></u>

Since the triangle is right use the tangent ratio to solve for x

$tan41^o=\frac{opposite}{adjacent}=\frac{12}{x}$

Multiply both sides by $x$

x × $tan41^o=12$ ( divide both sides by $tan41^o$ )

x = ≈ ( nearest tenth )

6 0

1 year ago