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NeX [460]
3 years ago
5

PLEASE HELP!!!!!!

Mathematics
2 answers:
sergejj [24]3 years ago
8 0

Answer:

y = StartFraction plus-or-minus StartRoot x + 4 EndRoot Over 3 EndFraction

Step-by-step explanation:

y = 9x² - 4

Make x the subject

9x² = y + 4

x² = (y + 4)/9

x = +/- sqrt(y + 4)/sqrt(9)

x = +/- sqrt(y + 4)/3

Interswitch variables

inverse = +/- sqrt(x + 4)/3

Harrizon [31]3 years ago
7 0

Answer:

The inverse is ±sqrt((x+4)/9)

Step-by-step explanation:

y = 9x^2 – 4

We want to find the inverse

Exchange x and y

x = 9y^2 -4

Solve for y

Add 4 to each side

x+4 = 9y^2 -4+4

x+4 = 9y^2

Divide each side by 9

(x+4)/9 = 9/9y^2

(x+4)/9 = y^2

Take the square root of each side

±sqrt((x+4)/9) = sqrt(y^2)

±sqrt((x+4)/9) = y

The inverse is ±sqrt((x+4)/9)

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Laura can weed the garden in 1 hour and 20 minutes and her husband can weed it in 1 hour and 30 minutes. How long will they take
Harrizon [31]
<h2>Hello!</h2>

The answer is:

It will take 42.35 minutes to weed the garden together.

<h2>Why?</h2>

To solve the problem, we need to use the given information about the rate for both Laura and her husband. We know that she can weed the garden in 1 hour and 20 minutes (80 minutes) and her husband can weed it in 1 hour and 30 minutes (90 minutes), so we need to combine both's work and calculate how much time it will take to weed the garden together.

So, calculating we have:

Laura's rate:

\frac{1garden}{80minutes}

Husband's rate:

\frac{1garden}{90minutes}

Now, writing the equation we have:

Laura'sRate+Husband'sRate=CombinedRate

\frac{1}{80}+\frac{1}{90}=\frac{1}{time}

\frac{1*90+1*80}{7200}=\frac{1}{time}

\frac{170}{7200}=\frac{1}{time}

\frac{17}{720}=\frac{11}{time}

\frac{17}{720}=\frac{1}{time}

\frac{17}{720}*time=1

time=1*\frac{720}{17}=42.35

Hence, we have that it will take 42.35 minutes to weed the garden working together.

Have a nice day!

8 0
4 years ago
Simplify. 1/3(1−1/4)^2 please
Strike441 [17]

Answer:

3/16

Step-by-step explanation:

1/3(1-1/4)^2

1/3(3/4)^2

1/3(9/16)

3/16

4 0
3 years ago
Read 2 more answers
A paper is in the form of a rectangle ABCD in which AB= 18 cm and BC=14cm.A semicircular portion with BC as diameter is cut off.
svetoff [14.1K]

Answer:

remaining portion is area= area of rectangle- area of semicircle

= 18*14 - 3.14*7^2

=252-154.86

=199.86cm^2

7 0
3 years ago
Manny is covering a book. The front of the book is 11.2 inches high and 7.3 inches wide. What is the area of the front of the bo
irina [24]

Answer:

81.76in^2

Step-by-step explanation:

Given data

Lenght of book=  11.2 inches

WIdth of book= 7.3 inches

We know that Area= Length* Width

Area= 11.2*7.3

Area= 81.76 in^2

Hence the area of the front of the book is is 81.76in^2

7 0
3 years ago
1/4 _ 1/5 is it &lt; = &gt;
Gre4nikov [31]

Answer:

1/4 > 1/5

Step-by-step explanation:

think of a candy bar. if you split it into 4 parts the prices would be bigger than if u had to break it into 5 parts. also remember that the smaller number eats the bigger number so the sign would be towards the 1/4

4 0
3 years ago
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