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koban [17]
3 years ago
13

How do you solve a system of equations approximately using graphs and tables

Mathematics
2 answers:
arlik [135]3 years ago
4 0

Answer:

Solve for y and x of the given equations and draw graph  for each equation , then find their intersect points of the given equations .

Step-by-step explanation:

suppose, we take system of equations

x+y=5(I equation)

x-y=5(II equation)

Now , we take I equation x+y=5

Draw a table for this equation By following steps

Put x=0 in I equation then we get value of y =5 from I equation

Now , put y=0 in the I equation we get value of x=5 from I equation.

Now , we get two points (0,5) and (5,0) and plot the graph for I equation.

I  equation x+y=5 interscet x -axis at x=5 and y- axis at y=5 .

Now, w etake II equation x-y=5  

Now , put x=0 in the II equation then  we get  value of y =-5

Again, put y=0 in the II equation x-y=5 then we get value of x =5.

We get  two points (0,-5) and (5,0) for II equation and plot graph .

the common point is (5,0) of two equations.Hence , the solution of two equation is (5,0).

Therefore, we can solve system of equations in this way.

Dominik [7]3 years ago
3 0
So... You have to solve for y, graph it, and then find where the lines intersect.You can take a table and put in all the x and y valuesThen graph it.. And see where it intersectsBecause usually these equations are lines
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2x(x - 3) + 7(x - 3)<br> Can I have an explanation on how it works factors
Nimfa-mama [501]

Answer:

Step-by-step explanation:

2x(x - 3) + 7(x - 3)

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reduce

2x^2 + x - 21

if this is equal to 0 then:

2x^2 + x - 21 = 0

factored:

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How that was done:

Divide the (2x^2) into (2x) and (x).

Divide the (-21) into (+7) and (-3). You choose these numbers so that their sum, when multiplied by (2x) and (-3), adds up to (+x).  

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Step-by-step explanation:

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Factor f(x)=4x²-15x-25 and then use zero-product property to find the zeros of the quadratic function. Show all work (Will Mark
Ostrovityanka [42]
<span>f(x)=4x²-15x-25
</span><span>f(x)=(4x + 5)(x - 5)

</span><span>zero-product property 
let </span>f(x)=(4x + 5)(x - 5) = 0
so
(4x + 5)(x - 5) = 0
4x +5 = 0
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x - 5 =0
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answer
factor: (4x + 5)(x - 5)
x = 5 and x = -1.25

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3 years ago
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