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3 years ago

How many oz are in 3/8 lb.

2 answers:

8 0

There are six ounces in 3/8 lb. There are sixteen ounces in one pound, so you multiply 3 by 2 because 8 times 2 equals 16.

Kobotan [32]3 years ago

3 0

There are sixteen ounces in a pound. 3/8 x 16/1= 48/8=6 oz

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Can someone please give me the answer I will mark u brilliant

otez555 [7]

Answer:

4. option A ---> m = 65h

Step-by-step explanation:

According to the question it states that,

m --> number of miles traveled.
h --> <u>over</u> hours

Now if we look at the table we need to find the starting point, or in other words, how much distance traveled in 0 hours. So we would divide miles / hours.

*Four hours, the variable in the question and in the table says n, but the answer choices says h, so I am saying h for hours just if you were wondering on it.*

distance (m) / hours (h)

130 / 2 = 65

195 / 3 = 65

325 / 5 = 65

455 / 7 = 65

So, our starting point, or numbers of miles traveled in 0 hours was 65. Now let us form an equation.

m = 65h

I would appreciate if you give me the brainlist or not. Hope this helps and stay safe, happy, an healthy, thank you :) !!

3 0

3 years ago

Amy makes the following statement:

almond37 [142]

60%= 6/10= 3/5
10%= 1/10
1/10*3/5=3/50
The probability that it will snow and Amy will be late for school is 6%

5 0

3 years ago

Read 2 more answers

Find the equation of line b described below, in slope-intercept form

Serjik [45]

Given:

Line a is perpendicular to line b .

Line a passes through the points (1,-8) and (9,-12) .

Line b passes through the point (-8, -16).

To find:

The equation of b.

Solution:

Line a passes through the points (1,-8) and (9,-12) . So, slope of line a is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m_a=\dfrac{-12-(-8)}{9-1}$

$m_a=\dfrac{-12+8}{8}$

$m_a=\dfrac{-4}{8}$

$m_a=-\dfrac{1}{2}$

Product of slopes of two perpendicular lines is -1.

$m_a\times a_b=-1$

$-\dfrac{1}{2}\times a_b=-1$

$b=2$

Slope of line b is 2.

If a line passing through a point $(x_1,y_1)$ with slope m, then equation of line is

$y-y_1=m(x-x_1)$

Line b passing through (-8,-16) with slope 2. So, equation of line b is

$y-(-16)=2(x-(-8))$

$y+16=2(x+8)$

$y+16=2x+16$

Subtract 16 from both sides.

$y=2x$

Therefore, the equation of line b is $y=2x$ .

7 0

3 years ago

If an investment of $3000 grows to $4432.37 in eight years with interest compounded annually , what is the interest rate?

melamori03 [73]

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4432.37\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to r\%\to \frac{r}{100}\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &8
\end{cases}$

$\bf 4432.37=3000\left(1+\frac{r}{1}\right)^{1\cdot 8}\implies \cfrac{4432.37}{3000}=(1+r)^8
\\\\\\
\sqrt[8]{\cfrac{4432.37}{3000}}=1+r\implies \sqrt[8]{\cfrac{4432.37}{3000}}-1=r
\\\\\\
0.0500001086\approx r\qquad\qquad\cfrac{r\%}{100}\approx 0.0500001086
\\\\\\
r\%\approx 100\cdot 0.0500001086\implies r=\stackrel{\%}{5}$

6 0

3 years ago

Write an equation for your trend line?

Soloha48 [4]

Find two points on the graph that the line crosses through almost perfectly. It looks like (1,10) and (9,1) will do.

Use them to compute the slope:
m = (1 - 10) / (9 - 1)
= -9/8

Then set up the "point-slope form":
y - y0 = m * (x - x0)

You choose some point (x0, y0) that the line crosses through. We already know the line passes through (1,10) pretty well, so let's use that.

x0 = 1
y0 = 10

Now finish plugging into the equation:
y - 10 = -9/8 * (x - 1)

The above equation will work fine for an answer, but let's go a step further and solve for y.

y - 10 = -9/8x + 9/8
y = -9/8x + 9/8 + 10
y = -9/8x + 9/8 + 80/8
y = -9/8x + (9 + 80)/8
y = -9/8x + 89/8

4 0

3 years ago