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Goshia [24]
3 years ago
7

Mrs. Smith's third graders were learning patterns on a number chart. They were counting 74, 78, 82, 86. What were they skip coun

ting by and what number would come next in the sequence?
A: 2's, 88
B: 3's, 89
C: 4's, 90
D: 5's, 91
Mathematics
2 answers:
mihalych1998 [28]3 years ago
7 0
Well it would be C! so 78-74=4 so they are counting by 4's and 86+4=90 :33
iragen [17]3 years ago
7 0
It would be C because the pattern is skip counting by 4. The next number will be 90. Hope this helps !!
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Two angles are supplementary. The measure of one angle is 4 times the measure of the other angle. What is the measure of the sma
Alexus [3.1K]
ANSWER

The smaller angle is

y = 36 \degree



.EXPLANATION

Let the angles be
x \:  and \:  \: y

where y is the smaller angle.
Since they are supplementary, they will add up to 180°.


This implies that,

x + y = 180 \degree...(1)


If one angle is 4 times the other, we can then write the following equation,

x = 4y...(2)


We put equation (2) into equation (1) to get,



4y + y = 180 \degree


5y = 180 \degree


We divide through by 5 to obtain,

y = 36 \degree


This implies that,

x = 4(36)


x = 144 \degree
3 0
3 years ago
Three people build a rectangular shed 8 ft wide, 6 ft long, and 7 ft high. How many cubic feet does the shed contain?
dusya [7]
8x6x7= 336
Your answer is 336 ft^3
7 0
4 years ago
Am i correct? calculus
Advocard [28]
Check the picture below.

now, the "x" is a constant, the rocket is going up, so "y" is changing and so is the angle, but "x" is always just 15 feet from the observer.  That matters because the derivative of a constant is zero.

now, those are the values when the rocket is 30 feet up above.

\bf tan(\theta )=\cfrac{y}{x}\implies tan(\theta )=\cfrac{y}{15}\implies tan(\theta )=\cfrac{1}{15}\cdot y
\\\\\\
\stackrel{chain~rule}{sec^2(\theta )\cfrac{d\theta }{dt}}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}\implies \cfrac{1}{cos^2(\theta )}\cdot\cfrac{d\theta }{dt}=\cfrac{1}{15}\cdot \cfrac{dy}{dt}
\\\\\\
\boxed{\cfrac{d\theta }{dt}=\cfrac{cos^2(\theta )\frac{dy}{dt}}{15}}\\\\
-------------------------------\\\\


\bf cos(\theta )=\cfrac{adjacent}{hypotenuse}\implies cos(\theta )=\cfrac{15}{15\sqrt{5}}\implies cos(\theta )=\cfrac{1}{\sqrt{5}}\\\\
-------------------------------\\\\
\cfrac{d\theta }{dt}=\cfrac{\left( \frac{1}{\sqrt{5}} \right)^2\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{1}{5}\cdot 11}{15}\implies \cfrac{d\theta }{dt}=\cfrac{\frac{11}{5}}{15}\implies \cfrac{d\theta }{dt}=\cfrac{11}{5}\cdot \cfrac{1}{15}
\\\\\\
\cfrac{d\theta }{dt}=\cfrac{11}{75}

8 0
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12345 [234]
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Passes through 5,4 slope -3 ASAP
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The answer should be
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