Answer:
18
Step-by-step explanation:
First find out how many oranges he used to make the orange juice.
3/5 = 0.6
(45)(0.6)
27
He used 27 oranges to make the juice.
Now we can figure out how many oranges he has left.
45 - 27
18
Matthew has 18 oranges left.
Hope this helps!
Answer:
let the number be y
4(y-7)=48
y-7=48/4
y-7=12
y=12+7=19
I would appreciate if my answer is chosen as a brainliest answer
Answer:
The confidence interval for a population mean proportion mean should be constructed because the variable of interest is time to complete the round, which is a quantitative variable.
Step-by-step explanation:
A researcher with a golf association obtained a random sample of 25 rounds of golf on a Saturday morning and recorded the time it took to complete the round.
Time is the number of hours, so it is mean, and not proportion.
Variable of interest is time to complete the round, and since it is measured in hours it is a quantitative variable.
The answer is:
The confidence interval for a population mean proportion mean should be constructed because the variable of interest is time to complete the round, which is a quantitative variable.
You would write AB with a horizontal line segment over the letters A and B
So you would write this 
If you cannot draw that on your computer, then I would stick to saying "segment AB".
This question is incomplete, the complete question is;
A certain organization reported the following scores for two parts of the scholastic Aptitude test ( SAT)
Evidence-based Reading and writing : 533
Mathematics : 527
Assume the population standard deviation for each part is σ = 100.
What is the probability a sample of 66 test takers will provide a sample mean test score within 10 points of the population mean of 533 on the Evidence-based Reading and Writing part of the test?
Answer: the required probability is 0.582
Step-by-step explanation:
Given that;
Population mean = 533
sample size n = 66
population standard deviation σ = 100
σ of x bar = 100/√66 = 12.3091
Normal distribution with mean 533 and SD of 12.3091
P( 523 <x< 543 )
Z = 10 / 12.3091
Z = 0.8124, -0.8124
P( z < 0 0.8124) - P( z < -0.8124) { from table}
⇒ 0.7910 - 0.2090
= 0.582
Therefore, the required probability is 0.582
