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Korolek [52]
3 years ago
7

Four research teams each used a different method to collect data on how fast a new strain of maize sprouts. Assume that they all

agree on the sample size and the sample mean (in hours). Use the (confidence level; confidence interval) pairs below to select the team that has the smallest sample standard deviation.
A.Confidence Level: 99.7%; Confidence Interval: 42 to 48 
B.Confidence Level: 95%; Confidence Interval: 43 to 47
 C.Confidence Level: 68%; Confidence Interval: 44 to 46 
D.Confidence Level: 95%; Confidence Interval: 44 to 46
Mathematics
2 answers:
Westkost [7]3 years ago
5 0
<span>Confidence Level: 95%; Confidence Interval: 44 to 46</span>
Drupady [299]3 years ago
5 0

Answer:

D

Step-by-step explanation:

First of all we know that confidence interval includes

Mean + or - z critical value (std deviation)

The larger the confidence level the longer the confidence interval would be.

Here given the confidence level for four research teams each used a different method to collect data on how fast a new strain of maize sprouts

.Confidence Level: 99.7%; Confidence Interval: 42 to 48  

B.Confidence Level: 95%; Confidence Interval: 43 to 47

C.Confidence Level: 68%; Confidence Interval: 44 to 46  

D.Confidence Level: 95%; Confidence Interval: 44 to 46

Comparing B and D we find that D is having less std deviation as length is narrower.

Comparing D with C, we conclude that for same 44 to 46 C used only 68%

So C must have had higher std dev than D

Similarly A and D comparison shows that A has more longer interval and more std deviation.

So answer is D which has the smallest std dev

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7 0
3 years ago
The angle measures of triangle QRS are given:
Trava [24]

Answer:

x = 15°

Step-by-step explanation:

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7 0
3 years ago
Harriet thinks of a number.
umka2103 [35]
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6 0
3 years ago
Read 2 more answers
I will give brainliest to the best answer.
aniked [119]

Given that two digit numbers are used and one digit is drawn randomly.

Sample space = {10,11,...99}

n(S) = 90

32 is only one number favorable

Hence P(32) = 1/90

----------------------------

Odd numbers are exactly 45.

Hence prob (odd number) = 45/90 = 1/2

-------------------------------------

Multiples of 5 are 10,15,.....95

There are exactly 18 numbers.

Hence P(a multiple of 5) = 18/90 =1/5

Have an amazing day! <3

7 0
3 years ago
Given that x is an integer, what is the solution of <br>|x-1|<img src="https://tex.z-dn.net/?f=%20%5Cleqslant%201" id="TexFormul
Varvara68 [4.7K]

Answer:

see explanation

Step-by-step explanation:

Inequalities of the type | x | ≤ a always have solutions of the form

- a ≤ x ≤ a

Given

| x - 1 | ≤ 1 then

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0 ≤ x ≤ 2

Since we require an integer solution then x = 0, 1, 2

5 0
3 years ago
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