Answer:
The average rate of change of the given function
A(x) = 1
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given function f(x) = x² - 2x -4
And given that x = a = -1 and x=b = 4
The average rate of change of the given function
<u><em>Step(ii):-</em></u>
f(x) = x² - 2x -4
f(-1) = (-1)² - 2(-1) -4 = 1+2-4 = -1
f(4) = 4² -2(4) -4 = 16 -12 = 4
The average rate of change of the given function
<u><em>final answer:-</em></u>
The average rate of change of the given function
A(x) = 1
Answer:
Step-by-step explanation:
The amount of heat released when 12.0g of helium gas condense at 2.17 K is; -250 J
The latent heat of vapourization of a substance is the amount of heat required to effect a change of state of the substance from liquid to gaseous state.
However, since we are required to determine heat released when the helium gas condenses.
The heat of condensation per gram is; -21 J/g.
Therefore, for 12grams, the heat of condensation released is; 12 × -21 = -252 J.
Approximately, -250J.
Read more on latent heat:
brainly.com/question/19863536
Answer:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c.
Step-by-step explanation:
In order to solve this question, it is important to notice that the derivative of the expression (1 + sin(x)) is present in the numerator, which is cos(x). This means that the question can be solved using the u-substitution method.
Let u = 1 + sin(x).
This means du/dx = cos(x). This implies dx = du/cos(x).
Substitute u = 1 + sin(x) and dx = du/cos(x) in the integral.
∫((cos(x)*dx)/(√(1+sin(x)))) = ∫((cos(x)*du)/(cos(x)*√(u))) = ∫((du)/(√(u)))
= ∫(u^(-1/2) * du). Integrating:
(u^(-1/2+1))/(-1/2+1) + c = (u^(1/2))/(1/2) + c = 2u^(1/2) + c = 2√u + c.
Put u = 1 + sin(x). Therefore, 2√(1 + sin(x)) + c. Therefore:
∫((cos(x)*dx)/(√(1+sin(x)))) = 2√(1 + sin(x)) + c!!!
