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Alinara [238K]
3 years ago
13

Which statement could be used to prove to provide that the function f(x)= -4x+6 grows by equal differences over any x-interval o

f 4 units?
Mathematics
1 answer:
Ivahew [28]3 years ago
3 0

Find the Greatest Common Factorthe largest number that divides evenly into <span>4x<span>4x</span></span> and <span>-6<span>−6</span></span>?
It is <span>22</span>.
the highest degree of <span>xx</span> that divides evenly into <span>4x<span>4x</span></span> and <span>-6<span>−6</span></span>?
It is 1, since <span>xx</span> is not in every term.Multiplying the results above,
The GCF is <span>22</span>.

<span><span>2(<span><span>​2</span>​<span>​<span>4x</span></span><span>​​</span></span>−<span><span>​2</span>​<span>​6</span><span>​​</span></span>)

</span>
<span>−2(2x−3)</span>
</span>

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Total = {(1,1),(2,1),(3,1),(4,1),(5,1),(6,1),(1,2),(2,2),(3,2),(4,2),(5,2),(6,2),(1,3),(2,3),(3,3),(4,3),(5,3),(6,3),(1,4),(2,4),(3,4),(4,4),(5,4),(6,4),(1,5),(2,5),(3,5),(4,5),(5,5),(6,5),(1,6),(2,6),(3,6),(4,6),(5,6),(6,6)}

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n(S)=36

Let A and B represent the following events.

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B = The sum is less than or equal to 6.

B = {(1,1),(1,2),(1,3),(1,4),(1,5),(2,1),(2,2),(2,3),(2,4),(3,1),(3,2),(3,3),(4,1),(4,2),(5,1)}

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A∩B = {(1,3),(2,2),(3,1)}

n(A∩B) = 3

P(A)=\dfrac{n(A)}{n(S)}=\dfrac{3}{36}

P(B)=\dfrac{n(B)}{n(S)}=\dfrac{15}{36}

P(A\cap B)=\dfrac{n(A\cap B)}{n(S)}=\dfrac{3}{36}

We need to find the probability that the sum will be 4, given that the sum is less than or equal to 6.

P(\frac{A}{B})=\dfrac{P(A\cap B)}{P(B)}

P(\frac{A}{B})=\dfrac{\frac{3}{36}}{\frac{15}{36}}

P(\frac{A}{B})=\dfrac{3}{15}

P(\frac{A}{B})=\dfrac{1}{5}

P(\frac{A}{B})=0.2

Therefore, the required probability is 0.2.

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