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Snowcat [4.5K]
3 years ago
5

How do you do simultaneous equations by the method or substitution?​

Mathematics
1 answer:
ozzi3 years ago
5 0

Answer:

Here's the simplest example possible: let's say x + y = 3 and x - y = 1. Solve the second equation for x by adding y to both sides: (x - y) + y = 1 + y. So x = 1 + y. Take that value of x, and substitute it into the first equation given above (x + y = 3).

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Difference between 1 8/10 and 2 2/5
Eva8 [605]
The first step to solving this is converting these mixed numbers into improper fractions. You would do that by multiplying the denominator by the whole number and adding the numerator to that number; this number replaces the numerator. It would look something like this:

1 8/10   -->   18/10
2 2/5   -->   12/5

Now, to subtract the second fraction from the first one, the denominators of both fractions must be the same. We can make them the same by multiplying the second fraction by 2:

12/5 * 2/2 = 24/10

Now we can set up the equation as:

18/10 - 24/10 = -6/10   -->   -3/5

The answer is negative 3/5.

I hope this helps.
5 0
3 years ago
Which column represents the correct method for the proof of the following statement?
kramer

Answer:

90

Step-by-step explanation:

the colums add up to angle 1, which make angle 2 adjacent.

9-9=0

3 0
2 years ago
The function y= 19,800/x is a rational function. Use this function to answer each question. What are the asymptotes of the funct
Ilya [14]

Answer:

Step-by-step explanation:

Given the function y = 19800/x

Vertical asymptote occurs at when f(x) = 0 where;

f(x) is the denominator of the given function.

From the expression given: f(x) = x

Since f(x) => 0, hence x = 0

To get the horizontal asymptote, we will look at the degree of the numerator and denominator. If the degree of numerator is less than the denominator, the horizontal asymptote will be zero. From the function, we can see that the degree of the numerator is zero (being a constant) and that of the denominator is 1.

Since 0<1, hence the horizontal asymptote is 0

x = 0, y = 0

5 0
3 years ago
Read 2 more answers
Which of the following sets contain all roots of the polynomial
Zarrin [17]

All these given roots are contained in option C.

The given equation is :

9x^{3}+9x^{2}-4x-4=0

9x^{2}(x+1)-4(x+1)=0

(9x^{2}-4)(x+1)=0

9x^{2}-4=0,x+1=0

x^{2}=\frac{4}{9},x=-1

x=\frac{2}{3},x=-1

Roots = -1,\frac{-2}{3} ,\frac{2}{3}

Hence these lie in between (\frac{-3}{2} ,\frac{3}{2})


8 0
3 years ago
Algebra 2 inverse functions
Mashutka [201]

Answer:

The inverse function is:

{(1,8), (2,-1), (5,10), (-3,-3)}

Step-by-step explanation:

When a function is represented in the form of ordered pairs, the first element of each ordered pair is the input and the second element in each ordered pair is the output. In the inverse of a function the input becomes output and the output becomes input.

Given function is:

{(8,1), (-1,2), (10,5), (-3,-3)}

Reversing the order of elements of ordered pairs will given us the inverse function.

The inverse function is:

{(1,8), (2,-1), (5,10), (-3,-3)}

5 0
3 years ago
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