What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
lox (x) = -5
rewrite the equation in exponential form:
10^-5 = x
10^-5 = 1/10000
1/10000 = 0.00001
That is the correct answer.
Ayden bought 4 oranges.
Explanation:
4.20 divided by 6 will give you 0.7
0.7 times 4 gives you 2.8
1) 9x + 2 = x + 5 ---> 9x + 2 = 6
subtracted X from one side but not the other
2) 3(x-4) + 5 = 12 ---> 3x + 4 + 5 = 12
didn't distribute correctly: 3(x-4)
multiplied the X by 3 but not the -4
Answer: me + u is us
Step-by-step explanation:
