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2 years ago

Answer this question

Mathematics

2 answers:

Viefleur [7K]2 years ago

7 0

Answer:

Step-by-step explanation:

Given,

x = -2

Now, let's solve

${7x}^{4} + 3 {x}^{2} - 4$

Plug the value of x

$= 7 \times {( - 2)}^{4} + 3 \times {( - 2)}^{2} - 4$

A negative base raised to an even power equals a positive

$= 7 \times {2}^{4} + 3 \times {2}^{2} - 4$

Evaluate the power

$= 7 \times 16 + 3 \times 4 - 4$

Multiply the numbers

$= 112 + 12 - 4$

Add the numbers

$= 124 - 4$

Subtract the numbers

$= 120$

Hope this helps ...

Best regards!!

olasank [31]2 years ago

4 0

Answer:

c) 120

Step-by-step explanation:

f(x) = 7x^4 + 3x^2 - 4

f(-2) = 7(-2)^4 + 3(-2)^2 - 4 = 7(16) + 3(4) - 4 = 112 + 12 - 4 = 120

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Without using a calculator, what is 30% of 546? (You can round up to avoid decimal points)

madreJ [45]

Answer:

Hey there!

We can solve this by multiplying 0.3 by 546, which is about 164.

Hope this helps :)

5 0

2 years ago

Read 2 more answers

Stefan sells Jin a bicycle for $147 and a helmet for $18. The total cost for Jim is 150% of what Stefan spent originally to buy

soldi70 [24.7K]

Answer:

He spent $110.00 on both originally

Step-by-step explanation:

Add both prices too get 165

Then use the equation $\frac{150}{100}$ = $\frac{165}{x}$

cross multiply to get 150x=16500

Divide 16500 by 150 to get x alone

x= 110

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3 years ago

In 2018, the population will grow over 700,000.The population of a city in 2010 was 450,000 and was growing at a rate of 5% per

Firlakuza [10]

Answer:

The year is 2020.

Step-by-step explanation:

Let the number of years passed since 2010 to reach population more than 7000000 be 'x'.

Given:

Initial population is, $P_0=450,000$

Growth rate is, $r=5\%=0.05$

Final population is, $P=700,000$

A population growth is an exponential growth and is modeled by the following function:

$P=P_0(1+r)^x$

Taking log on both sides, we get:

$\log(P)=\log(P_0(1+r)^x)\\\log P=\log P_0+x\log (1+r)\\x\log (1+r)=\log P-\log P_0\\x\log(1+r)=\log(\frac{P}{P_0})\\x=\frac{\log(\frac{P}{P_0})}{\log(1+r)}$

Plug in all the given values and solve for 'x'.

$x=\frac{\log(\frac{700,000}{450,000})}{\log(1+0.05)}\\x=\frac{0.192}{0.021}=9.13\approx 10$

So, for $x > 9.13$ , the population is over 700,000. Therefore, from the tenth year after 2010, the population will be over 700,000.

Therefore, the tenth year after 2010 is 2020.

8 0

2 years ago

Mackenzie spent a total of $17.50 on Saturday afternoon.She bought a movie ticket for $7.25 and snacks for $4.95.She spent the r

Helga [31]

17.50-7.25-4.95=5.30/2=2.65

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2 years ago

STatiana [176]

Answer:

(e^3 / e^2n)

Step-by-step explanation:

isn't this the same question

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3 years ago

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