Question

Answer this question ​

Answer 1

Answer:

120

Step-by-step explanation:

Given,

x = -2

Now, let's solve

${7x}^{4} + 3 {x}^{2} - 4$

Plug the value of x

$= 7 \times {( - 2)}^{4} + 3 \times {( - 2)}^{2} - 4$

A negative base raised to an even power equals a positive

$= 7 \times {2}^{4} + 3 \times {2}^{2} - 4$

Evaluate the power

$= 7 \times 16 + 3 \times 4 - 4$

Multiply the numbers

$= 112 + 12 - 4$

Add the numbers

$= 124 - 4$

Subtract the numbers

$= 120$

Hope this helps ...

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Answer 2

Answer:

c) 120

Step-by-step explanation:

f(x) = 7x^4 + 3x^2 - 4

f(-2) = 7(-2)^4 + 3(-2)^2 - 4 = 7(16) + 3(4) - 4 = 112 + 12 - 4 = 120