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Andreyy89
2 years ago
11

HELP PLEASE!!!

Mathematics
2 answers:
yanalaym [24]2 years ago
8 0

Answerpic


Step-by-step explanation:


Dominik [7]2 years ago
3 0

Probability is the ratio of the desired outcomes to all possible outcomes. If there are no desired outcomes, the ratio is 0 over all possible outcomes, thus 0. If the event is all possible outcomes, the ratio is all possible outcomes over all possible outcomes, thus 1.

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Help a brother out!!! Math prom worth 20!! And explain please
Reil [10]
A.

ratio 1 to 1

alright
find the distance between the x values and the y values and seperate each into that ratio
1:1
A to B is (6,12) to (15,-4)
disatnce from 6 to 15 is 9, ratio would be 4.5:4.5=1:1
distance from 12 to -4 is 16, ratio would be 8:8=1:1
so the point would be (4.5,8)




b.
5:2
5+2=7
alright
A to C
(6,12) to (20,12)
distance from 6 to 20 is 14, 14/7=2, 2 times 5=10
distance from 12 to 12=0, so same coordinate
the point is (10,12)


c.
2+3=5

C to B
C is (20,12) and B is (15,-4)
distance from 20 to 15 is 5, so 2 is the x value
distance from 12 to -4 is 16, 16/5 times 2=32/5
the point is (2,32/5)
5 0
3 years ago
Which of the following statement is true? Select all that apply.​
jenyasd209 [6]

Answer:

1 and 2 are the answers i think

Step-by-step explanation:

8 0
2 years ago
Complete the question.
makvit [3.9K]

Answer:

6

Step-by-step explanation:

You are looking for the cross section of ask three circles. This is true for the smallest part, with the number 6 in it.

5 0
3 years ago
What is the solution to -3/4 x + 2 ≤ -7 ?
Dvinal [7]

Answer:

x ≥ 12

Step-by-step explanation:

Step 1: subtract 2 from both sides

Now you have; -3/4 x ≤ -9

Step 2: divide both sides by -3/4

Now you have x ≥ 12

(when dividing an inequality by a negative you have to flip the sign)

Therefore the answer is x ≥ 12

6 0
3 years ago
Read 2 more answers
can someone please answer this question for me with stood please? Also don't mind the weird doodle on the side..
brilliants [131]
Whats number question is it?

5 0
3 years ago
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