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never [62]
4 years ago
14

What is the third quartile of the following data set 24 20 35 43 28 36 25 29 44 21 37

Mathematics
1 answer:
seropon [69]4 years ago
4 0
Putting the data in ascending order, we get:
20, 21, 24, 25, 28, 29, 35, 36, 37, 43, 44
The median is in the middle and is 29.
The third quartile is the median of the set {35, 36, 37,43,44} and is therefore 37.
You might be interested in
The value of a book is $150 and decreases at a rate of 4% per year. Find the value of the book after 12 years
nevsk [136]
If it decreases at 4% every year, then its value becomes:

100% - 4% = 96% = 96/100 = 0.96

At the end of the 1 year its value becomes:  150*(0.96)

At the end of the 2 years its value becomes:  150*(0.96)*(0.96) = 150*(0.96)²

At the end of the 3 years its value becomes:  150*(0.96)*(0.96)*(0.96) = 150(0.96)³

So similarly at the end of 12 years, its value becomes 150*(0.96)¹²

=50*(0.96)¹²    simplify with calculator.

<span>≈ 91.91

Value at the end of 12 years becomes ≈ $</span><span>91.91

I hope this helps.
</span>
8 0
3 years ago
A cab company charges three dollars per cab ride plus an additional two dollar per mile driven how long is a cab ride that cost
Sav [38]

If the ride cost $9 then the miles will be 3 miles.

Step-by-step explanation:

In this question we are given:

Cost of one cab ride R = $3

Additional Cost per mile M = $2

So, Total cost of Cab Ride = $3 + $2M

If cost of cab ride is $9 then we need to find the miles

$3 + $2M = $9

Solving

$2M = $9 - $3

$2M = $6

=> M = $6/$2

M = 3 miles

So, if the ride cost $9 then the miles will be 3 miles.

Learn more:

You can find more information at:

brainly.com/question/11207748

brainly.com/question/1600376

Keywords: algebraic expressions, solve an equation

#learnwithBrainly

6 0
4 years ago
Help please will give a thanks !!
Vilka [71]

Answer:

7/9, -0.3, 11/2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A tennis tournament has 2n contestants. We want to pair them up for the first round of singles matches. Show that the number of
ddd [48]

There are

\dbinom{2n}2 = \dfrac{(2n)!}{2! (2n-2)!}

ways of pairing up any 2 members from the pool of 2n contestants. Note that

(2n)! = 1\times2\times3\times4\times\cdots\times(2n-2)\times(2n-1)\times(2n) = (2n-2)! \times(2n-1) \times(2n)

so that

\dbinom{2n}2 = \dfrac{(2n)\times(2n-1)\times(2n-2)!}{2! (2n-2)!} = \boxed{n(2n-1)}

4 0
2 years ago
How do you do this please help
fomenos

Answer: can u be more direct plz

Step-by-step explanation:

4 0
3 years ago
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