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3 years ago

9

A gallon of water weighs 8.354 pounds. Simon uses 11.81 gallons of water while taking a shower. About how many pounds of water d

id Simon use?

1 answer:

Mamont248 [21]3 years ago

8 0

8.354 x 11.81= 98.66074
Simon used 98.66074 pounds of water while taking a shower.

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When asked his age,Micheal said,"if you square my age,then subtract 12 times my age, the result is 85. "How old is she?

Mrac [35]

Answer:

Micheal is 17 years old.

Step-by-step explanation:

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3 years ago

For women aged 18-24, systolic blood pressures are normally distributed with a mean of 114.8 mm Hg and a standard deviation of

NNADVOKAT [17]

Answer:

0.0579 is the probability that mean systolic blood pressure is between 119 and 122 mm Hg for the sample.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 114.8 mm Hg

Standard Deviation, σ = 13.1 mm Hg

Sample size = 23

We are given that the distribution of systolic blood pressures is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling:

$\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{13.1}{\sqrt{23}} = 2.731$

P(blood pressure is between 119 and 122 mm Hg)

$P(119 \leq x \leq 122) = P(\displaystyle\frac{119 - 114.8}{2.731} \leq z \leq \displaystyle\frac{122-114.8}{2.731}) = P(1.537 \leq z \leq 2.636)\\\\= P(z \leq 2.636) - P(z < 1.537)\\= 0.9958 - 0.9379 = 0.0579= 5.79\%$

$P(119 \leq x \leq 122) = 5.79\%$

0.0579 is the probability that mean systolic blood pressure is between 119 and 122 mm Hg for the sample.

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3 years ago

How many solutions does this equation have?

goblinko [34]

1 answer namely x = 6

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John has four more nickels than dimes in his pocket, for a total of $1.25. Which equation could be used to determine the numbet

ahrayia [7]

So, you have to have your equation in terms of dimes. What you said about what he has: four more nickels than dimes in his pocket. Will help with our equation.
We know what a nickel and dime is worth. A nickel is .05 and a dime is .1
We don't know how many dimes are in his pocket, since we're trying to solve it.
.1x+(4+x).05=1.25;
In the parenthesis, it shows how there are four more nickels. Let's solve it now.
.1x + (4+x).05=1.25
.1x + .2+ .05x = 1.25; Let's add like terms.
.15x + .2 = 1.25; Subtract .2 from both sides.
.15x= 1.05
1.05÷.15= 7 =x
There are 7 dimes in his pocket, let's check our answer.
We now know there are 11 nickels, since there are four more nickels than dimes.
11(.05) +.1(7) = 1.25
.55+ .7 = 1.25
Now that we've tried it, we know there are 7 dimes in his pocket.
Tell me if this helps!

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