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sertanlavr [38]
4 years ago
10

The Earth’s total diameter is 12700 kilometers, with the solidified, ocean-covered crust that is at its thickest 35 kilometers w

ide. These massive sizes and the difference between them may be hard to imagine, so scale-model globes of the Earth shrink our tremendous planet down to a more manageable size. If the Earth’s diameter was shrunken to the size of a basketball (24.2 centimeters across), how thick would the Earth’s crust be in this model Earth, in centimeters?
Mathematics
1 answer:
Basile [38]4 years ago
7 0

Answer:

The correct answer is 0.0667 centimeters.

Step-by-step explanation:

Diameter of earth is 12700 kilometers.

Width of the solidified ocean crust is 35 kilometers.

Ratio between the diameter of the earth and the solidified crust is \frac{12700}{35} .

Now the earth is shrunken to a size of a basketball with the diameter as 24.2 centimeters. Let the thickness of the Earth's crust in this model be x centimeters.

Ratio between the diameter of the model earth and the solidified crust is \frac{24.2}{x} .

But this ratio of the real Earth and its model must be equal.

∴ \frac{12700}{35} = \frac{24.2}{x}

⇒ x = 0.0667 centimeters.

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PAGE 12
Yakvenalex [24]

Answer: The answer is option C: 10cm, 6cm and 8cm

Step-by-step explanation: A right angled triangle has an hypotenuse (the longest of all three sides) facing the 90 degree angle. Also a right angled triangle can be solved by means of the Pythagoras theorem which states that;

AC^2 = AB^2 + BC^2

Where AC is the hypotenuse (10cm) and AB (6cm) and BC (10cm) are the other two sides.

If that is the case, we can insert the values as given in option C to know whether or not they make up a right angled triangle. Therefore

10^2 = 6^2 + 8^2

100 = 36 + 64

100 = 100

Therefore the side lengths 10cm, 6cm and 8cm satisfies the requirements for a right angled triangle

3 0
4 years ago
Electrons and protons are particles in an atom with equal but opposite charges. Electrons have a negative charge and protons hav
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Change the charge because change the electrons change the charge
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3 years ago
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My new speaker costs $154.00, but I also had to
const2013 [10]

Answer:

$247.94

Step-by-step explanation:

6 0
3 years ago
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you have $240 to spend on an afternoon of indoor rock climbing with friends. there is a $45 group fee. in addition, each person
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240-45-6-4-75=188.94$

3 0
3 years ago
A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 444 gram setting. It is
ankoles [38]

Answer:

The null hypothesis is H_0: \mu = 444

The alternative hypothesis is H_1: \mu < 444

The p-value of the test is 0.1148 > 0.05, which means that the sample does not give enough evidence to conclude that the machine is underfilling the bags.

Step-by-step explanation:

A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 444 gram setting.

At the null hypothesis, we test if the machine works correctly, that is, the mean is of 444. So

H_0: \mu = 444

At the alternative hypothesis, we test if they are underfilling, that is, if the mean is of less than 444. So

H_1: \mu < 444

The test statistic is:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

444 is tested at the null hypothesis:

This means that \mu = 444

A 41 bag sample had a mean of 440 grams with a variance of 441.

This means that n = 41, X = 440, s = \sqrt{441} = 21

Value of the test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{440 - 444}{\frac{21}{\sqrt{41}}}

t = -1.22

P-value of the test:

Right-tailed test(test if the mean is less than a value), with 41 - 1 = 40 df and t = -1.22.

Using a t-distribution calculator, this p-value is of 0.1148

The p-value of the test is 0.1148 > 0.05, which means that the sample does not give enough evidence to conclude that the machine is underfilling the bags.

6 0
3 years ago
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