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3 years ago

Which of the following is the point and slope of the equation y + 9 = -2/3(x - 3)?

Mathematics

1 answer:

sattari [20]3 years ago

8 0

Answer:

-3,-9")

Step-by-step explanation:

it because y + 9 = -2/3(x - 3)?

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The ranger of the function x2+2x-8is allá

allsm [11]

Answer:

$\mathrm{Range\:of\:}x^2+2x-8:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:-9\:\\ \:\mathrm{Interval\:Notation:}&\:[-9,\:\infty \:)\end{bmatrix}$

Step-by-step explanation:

As the function is

$x^{2} +2x-8$

As we know that domain is the set of input values for which the function is defined.

Therefore,

$\mathrm{Domain\:of\:}\:x^2+2x-8\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

And range is defined as:

The set of the dependent variable for which the function is defined.

$\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0\:\mathrm{the\:range\:is}\:f\left(x\right)\ge \:y_v$

$a=1,\:\mathrm{Vertex}\:\left(x_v,\:y_v\right)=\left(-1,\:-9\right)$

$f\left(x\right)\ge \:-9$

Therefore,

$\mathrm{Range\:of\:}x^2+2x-8:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:-9\:\\ \:\mathrm{Interval\:Notation:}&\:[-9,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

Keywords: graph, domain, range

Learn more about domain and range from brainly.com/question/13856645

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3 years ago

What is the value of x? 27(x+4)=−6 −35 −25 25 35

Oksanka [162]

x = -38/9 !!!

27(x+4)=−6

Step 1: Simplify both sides of the equation.

27(x+4)=−6

(27)(x)+(27)(4)=−6 (Distribute)

27x+108=−6

Step 2: Subtract 108 from both sides.

27x+108−108=−6−108

27x=−114

Step 3: Divide both sides by 27.

27x/27=−114/27

x=−389

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