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Lina20 [59]
4 years ago
11

If a transversal crosses three non-parallel lines, how many pairs of vertical angles are formed? Explain your answer.

Mathematics
2 answers:
belka [17]4 years ago
7 0

Sample Response:

Six pairs of vertical angles are formed, two for each line crossed by the transversal.

Step-by-step explanation:


bulgar [2K]4 years ago
6 0
Each transversal crossing a line generates 2 pairs of vertical angles and for 3 transversal crossing the same line it will be 3 x2 = 6 pairs (or 12 angles)
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AnnyKZ [126]

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Probability = (4 / 52) * (3 / 51)

<span>Probability = 12 / 2652 = 0.004</span>

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4 years ago
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Need help with this question
kicyunya [14]

The equation of the line that passes through the points (2,1) and (5,-8) is

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3 years ago
Simplify. cos^2[(pi/2) - x] + cos^2[(pi/2) - x] + cos^2x
Ipatiy [6.2K]

Numerator
<span><span>cos<span>(<span>π/2</span>−x)</span></span>=<span>cos<span>(<span>π/2</span>)</span></span><span>cosx</span>+<span>sin<span>(<span>π/2</span>)</span></span><span>sinx</span></span>

now <span><span>cos<span>(<span>π/2</span>)</span></span>=0 and <span>sin<span>(<span>π/2</span>)</span></span>=1</span>

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Denominator

<span><span>sin<span>(<span>π/2</span>−x)</span></span>=<span>sin<span>(<span>π/2</span>)</span></span><span>cosx</span>+<span>cos<span>(<span>π/2</span>)</span></span><span>sinx</span></span>

simplifies to : cosx + 0 = cosx

<span>⇒<span><span>cos<span>(<span>π/2</span>−x)</span></span><span>sin<span>(<span>π/2</span>−x)</span></span></span>=<span><span>sinx/</span><span>cosx</span></span>=<span>tan<span>x</span></span></span>

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3 years ago
What is the answer<br> -8 + 3 + -8 – -3
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-8+3+-8--3
minusing a negativ means adding a positive
adding a negaative means minusing a positive
-8+3-8+3
-5-8+3
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4 years ago
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Please help me! I’ll name you brainiest!!!
Kamila [148]

Answer:

80

Step-by-step explanation:

first, put in (5x-4) for the x in g(x).

g(f(x))=(5x-4)^2 -1

now, FOIL and simplify.

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now, plug in -1 for x.

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25+40+15

80

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3 years ago
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