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Lerok [7]
3 years ago
6

HELP PLEASE

Mathematics
2 answers:
Lemur [1.5K]3 years ago
8 0

Answer:

False,

(-4, -1) is not a solution of the given system of equations

Step-by-step explanation:

Given the system of equations:

3x+8y =20            .......[1]

-5x+y =19              ......[2]

To determine (-4, -1) is a solution

Substitute x = -4 and y = -1 in both the equations, if they both satisfied then it is a solution.

3(-4)+8(-1)=20  

⇒-12-8 = 20

⇒-20 = 20         False.

-5(-4)+(-1)=19

⇒20-1 = 19

⇒19=19             True.

Since, the given statement is not true

because the ordered pair (-4, -1) does not satisfy the given system of equations.

docker41 [41]3 years ago
8 0

Answer:

False

Step-by-step explanation:

Given : The ordered pair (−4,−1) is a solution to the system of equations because when​ ​(−4,−1)​ is substituted into the equation, both equations are true.  3x+8y=20 and -5x+y=19

To find : Is the statement true or false?

Solution :

Let the equations,

3x+8y=20 .....Equation (1)

-5x+y=19 .......Equation (2)

Now, We have to determine that (-4,-1) is a solution of equations or not.

Substitute (-4,-1) in equation (1)

3x+8y=20

3(-4)+8(-1)=20

-12-8 = 20    

-20= 20    

False, The point is not satisfied the equation.

Substitute (-4,-1) in equation (2)

-5x+y=19

-5(-4)+(-1)=19

20-1 = 19    

19=19    

True, The point is satisfied the equation.

Since, The statement given is not true as ordered pair(-4,-1) is not satisfying the equation.

Therefore, The answer is false.

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The total weight of the bag that the salesman is carrying for selling a machine including some personal stuff is 13.9 Kg.

<h3>What is a fraction?</h3>

A fraction is a rational number that consists of a numerator and a denominator, used to represent a part of the whole thing.

<h3>Calculation:</h3>

It is given that,

A salesman is carrying a big bag for selling a machine.

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Andru [333]

Step-by-step explanation:

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Step-by-step explanation:

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The graph of the direct variation equation is a straight line through the origin.

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