2(x + y) + 3(x + y)
first distribute:
(multiply 2 into everything in the first parenthesis, and 3 into everything in the second)
2x + 2y + 3x + 3y
Second simplify (add all like terms (adding in this case) )
(2x + 3x) + (2y +3y)
5x + 5y
your answer is: 5x + 5y
hope this helps
Answer:
zero
Step-by-step explanation:
The answer to that question is best found by looking at the value of the <em>discriminant</em>.
For quadratic ax^2 +bx +c = 0, the value of the discriminant is ...
d = b^2 -4ac
Here, you have a=3, b=8, c=7, so the discriminant is ...
d = 8^2 -4(3)(7) = 64 -84 = -20
When the discriminant is negative, both solutions are complex (not real).
There are zero real solutions to this equation.
y = x² - 4x + 8
4x + y = 12
4x + y = 12
4x + (x² - 4x + 8) = 12
x² + 4x - 4x + 8 = 12
x² + 8 = 12
- 8 - 8
x² = 4
x = ±2
4x + y = 12
4(2) + y = 12
8 + y = 12
- 8 - 8
y = 4
4x + y = 12
4(-2) + y = 12
-8 + y = 12
+ 8 + 8
y = 20
(x, y) = (2, 4) and (-2, 20)
Answer:
8
Step-by-step explanation:
The rule is multpily by 2 so 4*2=8.