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Ber [7]
2 years ago
10

Select either relation (if the set is a relation but not a function), function (if the set is both a relation and a function), o

r neither (if the set is not a relation).
A = {(1, 2) (2, 2) (3, 2) (4, 2)}

relation
function
neither
Mathematics
1 answer:
galina1969 [7]2 years ago
6 0

Answer:  The correct options are

(A) relation

(B) function.

Step-by-step explanation:  We are given to check whether the following set is a relation or a relation and a function or neither :

A = {(1, 2) (2, 2) (3, 2) (4, 2)} .

Let us consider the following two sets :

U = {1, 2, 3, 4}  and  V = {2}.

Then, we see that the Cartesian Product of U and V is given by

U × V = {(1, 2) (2, 2) (3, 2) (4, 2)}.

Since a relation is a subset of Cartesian product, so the given set A is a relation.

Also, we know that a relation is a function if every first element is associated with one second element.

Since the relation A satisfies this condition, so the relation A is a function.

Thus, the given set A is both a relation and a function.

Option (A) and (B) are correct.

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Answer:

Step-by-step explanation:

A number that cannot be exactly expressed as a ratio of two integers.

An irrational number cannot be written as a simple fraction.

Pi is a famous irrational number.

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....................

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Please help on my hw, I'm not feeling good, and can't concentrate
sergiy2304 [10]

Answer:

Solution given:

f(x)=x²

g(x)=x+5

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now

23:

(fog)(x)=f(g(x))=f(x+5)=(x+5)²=x²+10x+25

24:

(gof)(x)=g(f(x))=g(x²)=x²+5

25:

(foh)(x)=f(h(x))=f(4x-6)=(4x-6)²=16x²-48x+36

26:

(hof)(x)=h(f(x))=h(x²)=4x²-6

27;

(goh)(x)=g(h(x))=g(4x-6)=4x-6+5=4x-1

28:

(hog)(x)=h(g(x))=h(x+5)=4(x+5)-6=4x+20-6=4x-14

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3 years ago
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