The sizing handles is known to be the small squares that appear in the corners and in the middle of the sides of a selected object's border.
<h3>What is sizing handles in MS Word?</h3>
The term sizing handles is known to be a tool that a person can use to be able to change a picture's size.
Note that if the mouse pointer is placed on a key that is of the sizing handles, the pointer alters to a double-headed arrow and a person can be able to then alter the size or shape of the image by dragging the sizing handle.
Note that it is often called handle, drag handle, sizing grip, resize corner, and therefore, The sizing handles is known to be the small squares that appear in the corners and in the middle of the sides of a selected object's border.
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If this is a true or false statement then the answer is true unless you have it on automatic save
Answer: provided in the explanation section
Explanation:
Given that:
Assume D(k) =║ true it is [1 : : : k] is valid sequence words or false otherwise
now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.
So, from here we have that D(k) is given by the following recorance relation:
D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise
Algorithm:
Valid sentence (s,k)
D [1 : : : k] ∦ array of boolean variable.
for a ← 1 to m
do ;
d(0) ← false
for b ← 0 to a - j
for b ← 0 to a - j
do;
if D[b] ∧ DICT s([b + 1 : : : a])
d (a) ← True
(b). Algorithm Output
if D[k] = = True
stack = temp stack ∦stack is used to print the strings in order
c = k
while C > 0
stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c
P = W (p) - 1
output stack
= 0 =
cheers i hope this helps !!!
Answer:
Following are the code to the given question:
#include <iostream>//header file
using namespace std;
int NumberOfPennies(int ND, int NP=0)//defining a method that accepts two parameters
{
return (ND*100 +NP);//use return keyword that fist multiply by 100 then add the value
}
int main() //main method
{
cout << NumberOfPennies(5,6) << endl; // Should print 506
cout << NumberOfPennies(4) << endl; // Should print 400
return 0;
}
Output:
506
400
Explanation:
In the method "NumberOfPennies" it accepts two parameters that are "ND and NP" that uses the return keyword that multiply 100 in ND variable and add in NP variable and return its values.
In the main method it it uses the cout method that call the by accepts value in parameter and print its value.
