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Advocard [28]
3 years ago
8

What are the coordinates of 1 and 3

Mathematics
1 answer:
Shalnov [3]3 years ago
8 0

Answer:

its 1 and 3 like xy = (1,3)

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Let f(x) = 6x-5 and g(x) = 2x-1. Find f • g
tankabanditka [31]

Hi

(6x-5) (2x-1) =  12x²-6x-10x+5 =  12x²-16x +5

3 0
3 years ago
Solve x^2 + 4x + 8 = 0
Mkey [24]

Answer:

x = -2 + 2 i or x = -2 - 2 i

Step-by-step explanation:

Solve for x:

x^2 + 4 x + 8 = 0

Subtract 8 from both sides:

x^2 + 4 x = -8

Add 4 to both sides:

x^2 + 4 x + 4 = -4

Write the left hand side as a square:

(x + 2)^2 = -4

Take the square root of both sides:

x + 2 = 2 i or x + 2 = -2 i

Subtract 2 from both sides:

x = -2 + 2 i or x + 2 = -2 i

Subtract 2 from both sides:

Answer:  x = -2 + 2 i or x = -2 - 2 i

8 0
3 years ago
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const2013 [10]

Answer:

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Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Use the Remainder Theorem to find the remainder for (2x^3-3x^2+6)/(x-1) and state whether or not the binomial is a factor of the
Bezzdna [24]

Answer:

Remainder= 5, and the binomial (x-1) is not a factor of the given polynomial.

Step-by-step explanation:

Given polynomial is (2x^3-3x^2+6) , we have to divide this with a binomial [tex}(x-1)[/tex] using remainder theorem.

Remainder theorem says if (x-a) is a factor then remiander would be f(a)

Therefore for (x-1), \ {we find}\  f(1)}

f(1)=(2\times 1^3-3\times1^2+6)\\1^3 =1\\1^2=1\\Substituting \ this \ above\\f(1)= (2-3+6)=5

Thus the remainder is 5 and since it is not 0 , so the binomial (x-1) is not a factor of the given polynomial.

6 0
3 years ago
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Which number is a factor of the prime factorization of 60? <br>3, 15, 9, or 6​
Anton [14]

Answer:3

Step-by-step explanation:

4 0
2 years ago
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