Question

1. The ordered pairs model an exponential function, where j is the function name and e is the input variable.

Answer 1

Answer:    Hi. I am sorry if this is a late answer, but here are the answer's I have. I just took the test so I am pretty sure these are correct:

#1.

2(5^e)

#3.

B)  f(t)=478(0.935)^t

I am so sorry but I don't have the answer for question #2. I hope you figure it out or someone else can help you. I hope I helped.  Good Luck!

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Answer 2

Answer:

1)  $j=2(5)^e$

2) option A

3)  option B

Step-by-step explanation:

1)  Given: The ordered pairs model an exponential function, where j is the function name and e is the input variable.

{(1, 10), (2, 50), (3, 250), (4, 1250)}

Let an exponential function $y=ab^x$

Now, put (1,10) ⇒10=ab      .....(1)

put (2,50) ⇒$50=ab^2$     ....(2)

divide (1) and (2)

we get b=5 then put back in (1)

we get 10=a(5)⇒ a=10/5= 2

therefore the required function is $y=2(5)^x$

For j is the function name and e is the input variable

the function is  $j=2(5)^e$

2) Given: The population of a pack of wolves is 88. The population is expected to grow at a rate of 2.5% each year.

To find: What function equation represents the population of the pack of wolves after t years

solution : $f(t) = P(1+r)^t$

where P-population , r- growth rate , t -time

putting value we get, $f(t) = 88(1+0.025)^t$

                $f(t) = 88(1.025)^t$

therefore, option A is correct

3) Given: Ramon bought a bicycle for $478. The value of the bicycle is expected to decrease at a rate of 6.5% each year.

To find: What function equation represents the value of the bicycle after t years.

solution : $f(t) = P(1-r)^t$

where P-population , r- decay rate , t -time

putting values we get,   $f(t) = 478(1-0.65)^t$

                                        $f(t) = 478(0.935)^t$

therefore, option B is correct