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3 years ago

What is the formula for the sequence below? 3, 6, 18, 5

1 answer:

7 0

This is a geometric sequence since there is a common ratio between each term. In this case, multiplying the previous term in the sequenceby 33 gives the next term. In other words, an=a1⋅rn−1an=a1⋅rn-1.

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Fourteen subtracted from 2 times a number is 28. Write an equation?

Alecsey [184]

Step-by-step explanation:

let the unknown number be x

1St step: twice the number is 2(x) =2x

2nd step: 2x -14

3rd step: 2x - 14=28...

5 0

3 years ago

PLS HELP PLS

mariarad [96]

The scale factor from Figure A to Figure B is 4

<h3>How to determine the scale factor from Figure A to Figure B?</h3>

From the question, we have the following statement:

Figure B is a scaled copy of Figure A.

The corresponding side lengths of figure A and figure B are:

Figure A = 10

Figure B = 40

The scale factor from Figure A to Figure B is then calculated as:

Scale factor = Figure B/Figure A

Substitute the known values in the above equation

Scale factor = 40/10

Evaluate the quotient

Scale factor = 4

Hence, the scale factor from Figure A to Figure B is 4

Read more about scale factor at

brainly.com/question/24968688

#SPJ1

8 0

1 year ago

The savings account offering which of these APRs and compounding periods offers the best APY?

zzz [600]

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\
$

$\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\
$

$\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1$

7 0

3 years ago

Read 2 more answers

HELP PLEASE ASAP<br> what is the mean of 210,160,200 ?

MrRissso [65]

To find the mean, add all the numbers then divide by the amount of numbers there are to find the average.

210+160+200=570

570÷3=190

Answer: 190

5 0

3 years ago

Read 2 more answers

Josh buys candy that costs $8 per pound. He will spend at most $88 on candy. What are the possible numbers of pounds he will buy

liberstina [14]

Answer:

11 pounds

Step-by-step explanation:

You would do 88 divided by 8 to get 11

3 0

4 years ago