Answer:
201.06in³ should be your answer
Answer: 
Step-by-step explanation:
Given
Length of rectangle is 
Perimeter must be greater than 40 ft
Suppose l and w be the length and width of the rectangle
So, the smallest width can be
Answer:
72 spheres are formed
Step-by-step explanation:
We start by calculating the volume of the metallic cylinder
Mathematically, we have this as;
V = pi * r^2 * h
V = pi * 21 * 14^2
V = 4116 π cm^3
The volume of each small sphere is;
V = 4/3 * pi * r^3
= 4/3 * π * 7/2^3 = 57.167 π cm^3
To get the number of small spheres, we simply divide the volumes
That will be 4116 pi / 57.167 pi = 72
Assuming that the exam weight is 100, you would need at least an 80 on the test
22/36 simplified is 11/18. I hope this helps. Tell me if you need an explanation! : )
