Answer:
$198,859.03
Step-by-step explanation:
The amortization formula is good for this. Fill in the given numbers and solve for the unknown.
A = P(r/n)/(1 -(1 +r/n)^(-nt))
where A is the monthly payment, P is the principal amount of the loan, r is the annual interest rate, n is the number of times per year interest is compounded, and t is the number of years.
1340.00 = P(0.0525/12)/(1 -(1 +0.0525/12)^(-12·20)) ≈ 0.00673844·P
P ≈ 1340/0.00673844 ≈ $198,859.03
The family can afford a loan for $198,859.
Answer:
30 each of 23% bars and 18 each of 79% bars
Step-by-step explanation:
If x is the number of 1 kg 23% copper bars, and y is the number of 1 kg 79% copper bars, then:
x + y = 48
0.23x + 0.79y = 0.44(48)
Substituting and solving:
0.23x + 0.79(48-x) = 0.44(48)
0.23x + 37.92 - 0.79x = 21.12
16.8 = 0.56x
x = 30
y = 48 - x
y = 18
You need 30 each of 23% bars and 18 each of 79% bars.
Owen is aroumd 4.87 feet tall also.
Answer:
(x+a) (x+b)=x(x+b)+a(x+b)=x²+bx+ax+ab=x²+x(a+b)+ab
