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2 years ago

Which expression is equivalent to the given expression? (-4ab)3

Mathematics

1 answer:

vampirchik [111]2 years ago

6 0

Answer:

-64a³b³

Step-by-step explanation:

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Solve the system of equation 2x + y = -4 and 5x – 3y = 1 by the method of elimination

Radda [10]

Step-by-step explanation:

first step while implementing the elimination method is to look at the numbers which can be multiplied to which in order to have like terms as solved below

as you can see in equation number 2 that the number three can be multiplied with equation 1 in order to have like terms so you can cancel them out

so , multiply 3 with the whole of equation 1

3( 2x + y = -4 )

= 6x + 3y = -12

( keep in mind the sign of the number)

5x -3 y = 1

now ,

we have

6x + 3y = -12

5x -3y = 1

as you can see that now we have like terms and when we add both these equations the like terms cancel out each other as they have opposite signs ( + - gives you - )

so , once you add the like terms this is what you will get

6x + 5x +3y-3y -12+1

= 11x + 0 - 11

then you can simplify this further for x first

11x = 11

x = 11/11

x = 1

now we have the value of x let's simply further for y

let's take equation 2

5(1) - 3y =1

5 -3y = 1

5-1 = 3y

4 = 3y

4/3 = y 

to confirm your values you can put these values in one of the two equations given initially , let's use equation two to check .

5x-3y = 1

( now let's place the values of x and y into the equation and see if our answer is 1 )

5 (1) - 3 (4/3)

= 5 - 4

= 1

it is correct

7 0

2 years ago

Solve for x and y 6/x+2y + 5/x-2y = -3 ; 3/x+2y + 7/x-2y = -6

Radda [10]

Step-by-step explanation:

Let

{1/(x+2y)} = u -----Eqn(1)

{1/(x-2y)} = v ------Eqn(2)

So, given equation can be rewritten as

⇛6u + 5v = -3 ---Eqn(3)

⇛3u + 7v = -6 -----Eqn(4)

On multiply equation (4) by 2, we get

⇛6u + 14v = -12 -----Eqn(5)

On subtracting equation (3) from equation (5), we get

⇛9v = -9

⇛v = -9/9

⇛v = -1 ----Eqn(6)

Put value of v in equation (3), we get

6u + 5v = -3

⇛6u + 5 * (-1) = -3

⇛6u -5 = -3

⇛6u = -3 + 5

⇛6u = 2

⇛u = 2/6

⇛u = (2÷2)/(6÷2)

⇛u = 1/3 -----Eqn(7)

Now, substituting value of u and v in equation (1) and equation (2), we get

{1/(x+2y)} = 1/3 and {1/(x-2y)} = -1

⇛x + 2y = 3 -----Eqn(8)

⇛x - 2y = -1 -------Eqn(9)

Now, add equation (8) and equation (9) , we get

⇛2x = 2

⇛x = 2/2

On substituting x = 1 in equation (8), we get

x + 2y = 3

⇛ 1 + 2y = 3

⇛2y = 3 - 1

⇛2y = 2

⇛y = 2/2

Therefore, x = 1 and y = 1

Answer: Hence the value of x and y is 1 and 1.

8 0

1 year ago

WILL UPVOTE! Factor the expression. 4r^2 − 49 =

chubhunter [2.5K]

Would it be
(2r-7)*(2r+7)

?

6 0

2 years ago

EAST MATH PLS HELP ASAP PLEASE PLEASE

serious [3.7K]

4(x+7)=8x-20

4x+28=8x-20

28=4x-20

48=4x

x=12

7 0

2 years ago

f the original price of a table is p and the sale price of the table is p−0.2p, which other expression represents the sale price

Sphinxa [80]

Answer:

0.2p is the correct

6 0

2 years ago